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Characteristics of Butterworth approximation

Short answer

The Butterworth response is maximally flat at ω=0, monotonic with no ripple, and has magnitude |T(jω)|^2=1/(1+ε^2 ω^(2n)). At ω=1 (ε=1) it is -3 dB. Roll-off is 20n dB/decade. All-pole, poles lie on a circle in the left half-plane, phase is fairly linear.

What are the characteristics of Butterworth low pass approximation?

The Butterworth (maximally flat) low-pass response has magnitude

∣T(jω)∣2=11+ε2ω2n|T(j\omega)|^2 = \frac{1}{1 + \varepsilon^2\omega^{2n}}

(normalized so that ωp\omega_p = 1 rad/s; with ε=1\varepsilon = 1 the half-power frequency is 1 rad/s). Its characteristics are:

  • Maximally flat at ω=0\omega = 0: the first 2n−12n-1 derivatives of ∣T(jω)∣2|T(j\omega)|^2 are zero at ω=0\omega = 0, so the passband is as flat as possible.
  • Monotonic: no ripple in the passband or the stopband; the gain falls continuously with frequency.
  • ∣T(j0)∣=1|T(j0)| = 1; at ω=1\omega = 1 (when ε=1\varepsilon = 1) ∣T∣=1/2|T| = 1/\sqrt{2} (−3 dB) for every order.
  • Roll-off of 20n20n dB/decade far into the stopband; the transition is wider than Chebyshev or elliptic for the same nn.
  • All-pole function: all transmission zeros are at ω=∞\omega = \infty.
  • Poles lie on a circle of radius ωo=ε−1/n\omega_o = \varepsilon^{-1/n} in the left-half s-plane, equally spaced by π/n\pi/n, symmetric about the real axis.
  • Phase is fairly linear (better than Chebyshev), with a moderate delay peak near the cut-off.
  • As n→∞n \to \infty the response approaches the ideal brick-wall.
 |T|
  1 |----.__
    |       `.   n = 2
0.707 - - - - :\.  n = 4
    |         : \ \.
    |         :  `. `-._
    +---------+---------`----> w
              1

✓ Answer checked by Claude Sonnet 5.5

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