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Two-port impedance model and series connection

Short answer

The impedance model expresses port voltages in terms of port currents via open-circuit impedance parameters: V1 = z11 I1 + z12 I2, V2 = z21 I1 + z22 I2. In a series connection, the same current flows through both networks at each port and voltages add, so the overall z-parameters are the sum of the individual z-parameters: [Z] = [Za] + [Zb].

Explain the impedance model for 2-port network. Describe the series combination of two 2-port networks.

Impedance model of a two-port

In the impedance (z-parameter) model the port voltages are expressed in terms of the port currents:

[V1V2]=[z11z12z21z22][I1I2]\begin{bmatrix} V_1 \\ V_2 \end{bmatrix} = \begin{bmatrix} z_{11} & z_{12} \\ z_{21} & z_{22} \end{bmatrix} \begin{bmatrix} I_1 \\ I_2 \end{bmatrix} z11=V1I1∣I2=0,z12=V1I2∣I1=0,z21=V2I1∣I2=0,z22=V2I2∣I1=0z_{11} = \left.\frac{V_1}{I_1}\right|_{I_2=0},\quad z_{12} = \left.\frac{V_1}{I_2}\right|_{I_1=0},\quad z_{21} = \left.\frac{V_2}{I_1}\right|_{I_2=0},\quad z_{22} = \left.\frac{V_2}{I_2}\right|_{I_1=0}

They are called open-circuit impedance parameters because each is measured with the other port open. z11,z22z_{11}, z_{22} are driving-point impedances; z12,z21z_{12}, z_{21} are transfer impedances. For a reciprocal network z12=z21z_{12}=z_{21} and the network can be represented by a T-equivalent:

     z11-z12        z22-z12
o----[Za]----+----[Zb]----o
             |
           [z12]
             |
o------------+------------o

Series combination of two two-ports

In a series connection the input ports of networks NaN_a and NbN_b are connected in series and the output ports are connected in series, so the same current flows through both networks at each port and the voltages add.

I1 ->                       <- I2
o----+---------------+----o
 V1a |      Na       | V2a
o----+---------------+----o
 |                        |
o----+---------------+----o
 V1b |      Nb       | V2b
o----+---------------+----o

Derivation. For each network:

V1a=z11aI1a+z12aI2a,V2a=z21aI1a+z22aI2aV1b=z11bI1b+z12bI2b,V2b=z21bI1b+z22bI2b\begin{aligned} V_{1a} &= z_{11a}I_{1a} + z_{12a}I_{2a}, & V_{2a} &= z_{21a}I_{1a} + z_{22a}I_{2a} \\ V_{1b} &= z_{11b}I_{1b} + z_{12b}I_{2b}, & V_{2b} &= z_{21b}I_{1b} + z_{22b}I_{2b} \end{aligned}

Series connection gives I1=I1a=I1bI_1 = I_{1a} = I_{1b}, I2=I2a=I2bI_2 = I_{2a} = I_{2b}, V1=V1a+V1bV_1 = V_{1a}+V_{1b}, V2=V2a+V2bV_2 = V_{2a}+V_{2b}. Adding:

V1=(z11a+z11b)I1+(z12a+z12b)I2V2=(z21a+z21b)I1+(z22a+z22b)I2\begin{aligned} V_1 &= (z_{11a}+z_{11b})I_1 + (z_{12a}+z_{12b})I_2 \\ V_2 &= (z_{21a}+z_{21b})I_1 + (z_{22a}+z_{22b})I_2 \end{aligned} [Z]=[Za]+[Zb][Z] = [Z_a] + [Z_b]

So the z-parameters of a series combination are the sums of the individual z-parameters. This holds only if each port still carries equal and opposite currents in its two terminals after connection (Brune's test); it is always satisfied when both networks have a common ground line (e.g. three-terminal networks) or an ideal 1:1 transformer is used for isolation.

✓ Answer checked by Claude Sonnet 5.5

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