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Series connection of two-port networks

Short answer

A two-port network has two pairs of terminals (input and output) with port currents entering one terminal and leaving the other. In a series connection, input ports are in series and output ports in series, so currents are common and voltages add, yielding overall z-parameters as the sum of individual z-parameters: [Z] = [Za] + [Zb], provided Brune's test is satisfied.

What do you mean by 2-port network? Explain the series connection of two 2 port networks with figure and derivation.

Two-port network

A two-port is a network with two pairs of terminals (an input port 1-1′ and an output port 2-2′), where the current entering one terminal of a port leaves by the other terminal of the same port.

 I1 ->                 <- I2
 o------+---------+------o
 +      |         |      +
 V1     |   N     |      V2
 -      |         |      -
 o------+---------+------o
 1'                      2'

It is described by four parameters relating V1,I1,V2,I2V_1, I_1, V_2, I_2, e.g. the z-parameters V1=z11I1+z12I2V_1 = z_{11}I_1 + z_{12}I_2, V2=z21I1+z22I2V_2 = z_{21}I_1 + z_{22}I_2.

Series connection of two two-ports

In a series connection the input ports of networks NaN_a and NbN_b are connected in series and the output ports are connected in series, so the same current flows through both networks at each port and the voltages add.

I1 ->                       <- I2
o----+---------------+----o
 V1a |      Na       | V2a
o----+---------------+----o
 |                        |
o----+---------------+----o
 V1b |      Nb       | V2b
o----+---------------+----o

Derivation. For each network:

V1a=z11aI1a+z12aI2a,V2a=z21aI1a+z22aI2aV1b=z11bI1b+z12bI2b,V2b=z21bI1b+z22bI2b\begin{aligned} V_{1a} &= z_{11a}I_{1a} + z_{12a}I_{2a}, & V_{2a} &= z_{21a}I_{1a} + z_{22a}I_{2a} \\ V_{1b} &= z_{11b}I_{1b} + z_{12b}I_{2b}, & V_{2b} &= z_{21b}I_{1b} + z_{22b}I_{2b} \end{aligned}

Series connection gives I1=I1a=I1bI_1 = I_{1a} = I_{1b}, I2=I2a=I2bI_2 = I_{2a} = I_{2b}, V1=V1a+V1bV_1 = V_{1a}+V_{1b}, V2=V2a+V2bV_2 = V_{2a}+V_{2b}. Adding:

V1=(z11a+z11b)I1+(z12a+z12b)I2V2=(z21a+z21b)I1+(z22a+z22b)I2\begin{aligned} V_1 &= (z_{11a}+z_{11b})I_1 + (z_{12a}+z_{12b})I_2 \\ V_2 &= (z_{21a}+z_{21b})I_1 + (z_{22a}+z_{22b})I_2 \end{aligned} [Z]=[Za]+[Zb][Z] = [Z_a] + [Z_b]

So the z-parameters of a series combination are the sums of the individual z-parameters. This holds only if each port still carries equal and opposite currents in its two terminals after connection (Brune's test); it is always satisfied when both networks have a common ground line (e.g. three-terminal networks) or an ideal 1:1 transformer is used for isolation.

✓ Answer checked by Claude Sonnet 5.5

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