- 2076 Asoj · 3 marks
General state of plastic equilibrium
Short answer
Every point in the soil mass is on the verge of shear failure: shear stress equals c+σ tanφ, and the Mohr circle touches the failure envelope. In the active state horizontal stress reduces to Kaσv−2c√Ka; in passive it becomes Kpσv+2c√Kp. The concept forms the basis of Rankine’s earth pressure theory.
What do you understand by "General State of Plastic Equilibrium"?
A soil mass is in a state of plastic equilibrium when every point in it is on the verge of shear failure; the shear stress at each point equals the shear strength given by the Mohr-Coulomb criterion . The Mohr circle of stress at every point then just touches the failure envelope.
- Rankine's general state: this condition exists throughout the whole semi-infinite soil mass, which happens when the soil is stretched or compressed horizontally enough.
- Active state: the soil expands horizontally (e.g. the wall moves away). The vertical stress is the major principal stress and the horizontal stress falls to the minimum, .
- Passive state: the soil is compressed horizontally. The horizontal stress becomes the major principal stress, .
- The failure planes make an angle of with the major principal plane. This is to the horizontal in the active state and to the horizontal in the passive state.
It is the basis of Rankine's earth pressure theory.
✓ Answer checked by Claude Sonnet 5.5
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