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Settlement of pile group in sand

Short answer

Group settlement in sand is larger than single pile. Methods: Vesic's S_g = S √(B_g/D); Meyerhof's SPT formula S_g = 2 q √B_g I / N_bar with I = 1−L/(8B_g); equivalent raft method from a raft at 2/3 L depth with 2:1 spread; and elastic interaction methods.

Describe the various methods of determining the settlement of pile group in sand.

The settlement of a pile group in sand is greater than that of a single pile carrying the same load per pile, as a larger volume of soil is stressed. The main methods are:

  1. Vesic's method (empirical):
Sg=SBgDS_g = S\sqrt{\frac{B_g}{D}}

where SS is the settlement of a single pile at the same working load, BgB_g is the width of the group and DD the pile diameter.

  1. Meyerhof's SPT method:
Sg (mm)=2qBg INˉ,I=1−L8Bg≥0.5S_g\ (\text{mm}) = \frac{2q\sqrt{B_g}\,I}{\bar N},\qquad I = 1 - \frac{L}{8B_g} \ge 0.5

where qq is the net pressure on the group (kN/m²), BgB_g is in metres, LL is the length of pile embedded in the bearing stratum and Nˉ\bar N the average SPT value within a depth BgB_g below the tip (for CPT: Sg=qBgI2qcS_g = \dfrac{qB_gI}{2q_c}).

  1. Equivalent raft method: the pile load is assumed to act on an imaginary raft of the group size at a depth 23L\tfrac{2}{3}L from the top (for friction piles) with a 2:1 load spread, and the settlement of the raft is computed from elasticity or from SPT/plate test data.

  2. Elastic (interaction) methods (Poulos): settlement from interaction factors between piles.

✓ Answer checked by Claude Sonnet 5.5

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