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Tension cracks in cohesive backfill

Short answer

Tension cracks form to depth z0=2c/γ, eliminating tensile pressure. The active pressure acts only below z0 as a triangle with base γH-2c. The total thrust is Pa = ½(γH-2c)(H-z0), acting at (H-z0)/3 above the base. Cracks must be considered; water filling them adds hydrostatic pressure.

How do tension cracks influence the distribution of active earth pressure in purely cohesive soils?

In a purely cohesive soil (ϕ=0\phi=0) the active pressure at depth zz is pa=γz−2cp_a = \gamma z - 2c, which is negative (tension) near the surface.

  • The tension zone extends to a depth z0=2cγz_0 = \dfrac{2c}{\gamma} (zero pressure point). Soil cannot carry tension for long, so tension cracks form to this depth and the soil there gives no pressure on the wall.
  • The pressure diagram is therefore a triangle from z0z_0 to the base, with maximum value γH−2c\gamma H - 2c at the bottom. Thus the active thrust is
Pa=12(γH−2c)(H−z0)=12γH2−2cH+2c2γP_a = \tfrac12(\gamma H-2c)(H-z_0) = \tfrac12\gamma H^2 - 2cH + \frac{2c^2}{\gamma}

and it acts at (H−z0)/3(H-z_0)/3 above the base.

  • Neglecting the cracks (taking tension) would under-estimate the thrust. If the cracks fill with water, an extra hydrostatic thrust 12γwz02\tfrac12\gamma_w z_0^2 acts on the wall and increases pressure.

✓ Answer checked by Claude Sonnet 5.5

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