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Tension crack and active pressure, layered clay

Short answer

Tension crack depth z0 = 2c1/γ1 = 2.0 m. Ignoring tension, active thrust is 111 kN/m horizontally, acting 1.24 m above the base.

A 6 m high vertical wall supports a saturated cohesive backfill with horizontal surface. The top 3 m of backfill weighs 18 kN/m318\ \text{kN/m}^3 and has cohesion of 18 kN/m218\ \text{kN/m}^2. The bulk unit weight and cohesion of the bottom 3 m of the wall are 20 kN/m320\ \text{kN/m}^3 and 25 kN/m225\ \text{kN/m}^2 respectively. What is the likely depth of tension crack? If the tension crack develops, what will be the active earth pressure? Draw the pressure distribution diagram and determine the point of application of the resultant pressure.

Data: H=6H = 6 m; top 3 m: γ1=18\gamma_1 = 18, c1=18c_1 = 18; bottom 3 m: γ2=20\gamma_2 = 20, c2=25c_2 = 25. Saturated clay is taken as ϕu=0\phi_u = 0, so Ka=1K_a = 1 and pa=γz−2cp_a = \gamma z - 2c.

Depth of tension crack (where pa=0p_a = 0 in the top layer):

z0=2c1γ1=2×1818=2.0 mz_0 = \frac{2c_1}{\gamma_1} = \frac{2\times18}{18} = 2.0\ \text{m}

Pressures (kN/m2^2)

  • z=0z=0: −36-36 (tension, ignored); z=2z = 2 m: 00.
  • z=3z = 3 m (top layer): 18×3−36=18.018\times3 - 36 = 18.0.
  • z=3z = 3 m (bottom layer): 54−2×25=4.054 - 2\times25 = 4.0.
  • z=6z = 6 m: 54+20×3−50=64.054 + 20\times3 - 50 = 64.0.
 0 |
   | crack zone (2 m)
 2 |\
   | \
 3 |--18 / 4
   |      \
   |       \
 6 |--------64

Forces (per metre) and arm above the base

PartForce (kN/m)Arm (m)Moment
Top layer triangle: 0.5 x 1 x 189.003.33330.00
Bottom layer trapezoid: 3 x (4+64)/2102.001.059108.0
Total111.00138.0

The trapezoid has parallel sides 4 (top) and 64 (at the base) and height 3 m, so its centroid is measured from the base side:

yˉ=3 (2×4+64)3 (4+64)=1.059 m\bar y = \frac{3\,(2\times4+64)}{3\,(4+64)} = 1.059\ \text{m} yˉ=138.0/111.0=1.24 m above the base\bar y = 138.0/111.0 = 1.24\ \text{m above the base}

Answer: tension crack depth =2.0= 2.0 m; active thrust Pa=111P_a = 111 kN/m (horizontal), acting 1.24 m above the base of the wall.

✓ Answer checked by Claude Sonnet 5.5

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