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Physical significance of flexibility and stiffness matrices

Short answer

Flexibility matrix [F] gives displacements {Δ} = [F]{P}; element f_ij is displacement at i from a unit force at j, measuring softness. Stiffness matrix [K] gives forces {P} = [K]{Δ}; k_ij is force at i for unit displacement at j with other coordinates fixed, measuring stiffness. They are symmetric and [K] = [F]^{-1}.

Explain the physical significance of flexibility and stiffness matrices with suitable examples.

Flexibility matrix [F][F]

Each element fijf_{ij} is the displacement at coordinate ii caused by a unit force at coordinate jj. The relation is {Δ}=[F]{P}\{\Delta\} = [F]\{P\}. It measures how soft the structure is: a large fijf_{ij} means a small force gives a large displacement. Column jj is the deflected shape produced by a unit load at jj. Diagonal terms are always positive, and the matrix is symmetric (fij=fjif_{ij} = f_{ji}, Maxwell's theorem). It exists only for a stable, restrained structure and is the matrix used in the force method.

Stiffness matrix [K][K]

Each element kijk_{ij} is the force needed at coordinate ii to give a unit displacement at coordinate jj while all other coordinates are held fixed. The relation is {P}=[K]{Δ}\{P\} = [K]\{\Delta\}. It measures how stiff the structure is: column jj is the set of restraint forces that holds the structure in the shape of a unit displacement at jj. Diagonal terms are positive, and the matrix is symmetric. It is used in the displacement method.

The two are inverses: [K]=[F]−1[K] = [F]^{-1}.

Example: cantilever of length LL

Coordinates: 1 = vertical deflection at the free end, 2 = rotation at the free end.

[F]=[L33EIL22EIL22EILEI],[K]=[F]−1=[12EIL3−6EIL2−6EIL24EIL][F] = \begin{bmatrix} \dfrac{L^3}{3EI} & \dfrac{L^2}{2EI} \\[2mm] \dfrac{L^2}{2EI} & \dfrac{L}{EI} \end{bmatrix}, \qquad [K] = [F]^{-1} = \begin{bmatrix} \dfrac{12EI}{L^3} & -\dfrac{6EI}{L^2} \\[2mm] -\dfrac{6EI}{L^2} & \dfrac{4EI}{L} \end{bmatrix}
  • f11=L3/3EIf_{11} = L^3/3EI is the tip deflection due to a unit tip load.
  • k22=4EI/Lk_{22} = 4EI/L is the moment needed at the tip to give a unit rotation when the tip deflection is held zero.
  • Note k11=12EI/L3≠1/f11=3EI/L3k_{11} = 12EI/L^3 \neq 1/f_{11} = 3EI/L^3. The stiffness is not the reciprocal of the flexibility for a matrix, because the stiffness holds the other coordinate fixed while the flexibility leaves it free.

✓ Answer checked by Claude Opus 5.5 (high effort)

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