- 2072 Chaitra · 13 marks
Flexibility matrix: reactions at E and A, BMD
Short answer
Release hinge at E, take horizontal and vertical reactions as redundants; flexibility matrix compatibility yields H_E = 74.68 kN (left), V_E = 369.24 kN (up). At fixed base A: H_A = 54.68 kN (right), V_A = 380.76 kN (up), M_A = 175.80 kNm (clockwise).
Determine the reactions at support E and A and draw bending moment diagram of the frame shown in figure below by using the flexibility matrix method (force method). [Figure: frame; column AB (2EI) of 10 m with A fixed, 20 kN horizontal at B, with a 7 m dimension marked; beam BC-D (2EI) of 10 m carrying 75 kN/m UDL; column DE (EI) of 5 m, E hinged.]
Reading of the figure: A (0, 0) is fixed; column AB is 10 m high () with a 20 kN horizontal load (towards the right) at 7 m above A; beam BD is 10 m long () with 75 kN/m over its whole length; column DE is 5 m long (), so E is 5 m above the level of A, and E is hinged.
. Release the hinge at E: = horizontal reaction (), = vertical reaction (). The primary structure is a cantilever fixed at A.
B ================= D 75 kN/m
| |
| 20 kN -> | 5 m
| E (hinge)
| 10 m
A (fixed)
Primary-structure moments (+ tension on the inner face)
- : at B, kNm; at the 20 kN level, ; at A, kNm; the beam falls parabolically from at B to 0 at D.
- (unit horizontal force at E): DE from 0 at E to 5 at D; beam constant 5; column from 5 at B to at A.
- (unit vertical force at E): beam from 10 at B to 0 at D; column constant 10.
Flexibility matrix and load vector (in units)
Compatibility:
Final bending moments (kNm)
| Section | ||||
|---|---|---|---|---|
| A | -3890.00 | -5.00 | 10.00 | 175.80 |
| Q (20 kN level) | -3750.00 | 2.00 | 10.00 | -206.96 |
| B (column) | -3750.00 | 5.00 | 10.00 | -431.00 |
| mid BD | -937.50 | 5.00 | 5.00 | 535.30 |
| D (beam) | 0.00 | 5.00 | 0.00 | -373.40 |
| E | 0.00 | 0.00 | 0.00 | 0.00 |
Maximum sagging moment in the beam: 535.52 kNm at 5.08 m from B.
Reactions
- E (hinge): kN (towards the left), kN ()
- A (fixed): kN (towards the right), kN (), kNm (clockwise)
Check: : ; : kN.
Answer: at E, kN (towards the left) and kN (upward); at A, kN (towards the right), kN (upward) and kNm (clockwise).
✓ Answer checked by Claude Opus 5.5 (high effort)
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