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ILD: reaction at B, propped cantilever 12 m

Short answer

Use Muller-Breslau: RB = x^2(3L-x)/(2L^3) for a propped cantilever of span 12 m. Ordinates at 3 m intervals are 0, 0.0859, 0.3125, 0.6328, 1, positive throughout and zero at A.

Draw influence line diagram for reaction at support B of the propped cantilever beam shown in figure below. Determine ordinates at 3 m interval. [Figure: beam AB, A fixed, B roller, span 12 m. Printed as the alternative (OR) to the focal point question above.]

Sign convention: sagging moment (+), hogging moment (-); shear positive when the left part tends to go up; reaction positive upward. Ordinates are for a unit load moving along the beam.

Method (Muller-Breslau)

Propped cantilever AB of span L=12L = 12 m: A fixed, B roller, constant EIEI. Remove the support at B and give B a unit upward displacement. The ILD for RBR_B is the deflected shape of the cantilever AB (fixed at A) scaled so that the ordinate at B equals 1.

By Maxwell's reciprocal theorem, the deflection at B due to a unit load at xx from A equals the deflection at xx due to a unit load at B. So

RB(x)=δBxfBB=x2(3L−x)/6EIL3/3EI=x2(3L−x)2L3R_B(x) = \frac{\delta_{Bx}}{f_{BB}} = \frac{x^2(3L-x)/6EI}{L^3/3EI} = \frac{x^2(3L-x)}{2L^3}

Sample: x=9x = 9 m: RB=92(3×12−9)2×123=0.6328R_B = \dfrac{9^2(3\times12 - 9)}{2\times12^3} = 0.6328.

Ordinates (3 m interval)

x from A (m)036912
RBR_B00.08590.31250.63281

ILD shape

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The ordinate is 0 at A (a load at the fixed support is carried by A), increases with zero slope at A and reaches 1 at B. It is positive throughout, so a downward load always increases RBR_B. A UDL over the whole span gives RB=w×R_B = w\times (area of the ILD) =3wL8= \dfrac{3wL}{8}.

✓ Answer checked by Claude Opus 5.5 (high effort)

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