- Asked 2/25
- 2069 Asar · 5 marks
ILD: reaction at B, propped cantilever 10 m
Short answer
Use Muller-Breslau: RB = x^2(3L-x)/(2L^3) for a propped cantilever of span 10 m. Ordinates at 2 m intervals are 0, 0.056, 0.208, 0.432, 0.704, 1, positive throughout and zero at A.
Draw influence line diagram for the reaction at B of the propped cantilever beam shown in figure below. Find the ordinates at 2 m interval. [Figure: beam AB, A fixed, B roller, span 10 m.]
Sign convention: sagging moment (+), hogging moment (-); shear positive when the left part tends to go up; reaction positive upward. Ordinates are for a unit load moving along the beam.
Method (Muller-Breslau)
Propped cantilever AB of span m: A fixed, B roller, constant . Remove the support at B and give B a unit upward displacement. The ILD for is the deflected shape of the cantilever AB (fixed at A) scaled so that the ordinate at B equals 1.
By Maxwell's reciprocal theorem, the deflection at B due to a unit load at from A equals the deflection at due to a unit load at B. So
Sample: m: .
Ordinates (2 m interval)
| x from A (m) | 0 | 2 | 4 | 6 | 8 | 10 |
|---|---|---|---|---|---|---|
| 0 | 0.056 | 0.208 | 0.432 | 0.704 | 1 |
ILD shape
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The ordinate is 0 at A (a load at the fixed support is carried by A), increases with zero slope at A and reaches 1 at B. It is positive throughout, so a downward load always increases . A UDL over the whole span gives (area of the ILD) .
✓ Answer checked by Claude Opus 5.5 (high effort)
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