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ILD: fixed-end moment of propped cantilever

Short answer

The ILD is entirely hogging, zero at ends. Ordinates at 2 m intervals: 0, -1.44, -1.92, -1.68, -0.96, 0 at x=0,2,4,6,8,10 m. Peak -1.92 at 4 m.

Draw ILD for reaction moment at the fixed support of the propped cantilever beam of span 10 m. Take ordinate interval as 2 m.

Sign convention: sagging moment (+), hogging moment (-); shear positive when the left part tends to go up; reaction positive upward. Ordinates are for a unit load moving along the beam.

Method

Propped cantilever AB, L=10L = 10 m, A fixed, B roller. The reaction moment at A is the moment at the fixed support (hogging, so negative in the above convention). Muller-Breslau: replace the fixed support by a hinge and give it a unit rotation; the deflected shape of the beam gives the ILD.

Analytically, with a unit load at xx from A, a=xa = x, b=L−xb = L - x: fixed-end moment at A is ab2/L2ab^2/L^2 and the fixed-end moment at B is a2b/L2a^2b/L^2. Releasing B (roller) carries half of the latter to A:

MA=ab2L2+a2b2L2=x(L−x)(2L−x)2L2(hogging)M_A = \frac{ab^2}{L^2} + \frac{a^2 b}{2L^2} = \frac{x(L-x)(2L-x)}{2L^2}\quad(\text{hogging})

Sample: x=4x = 4: MA=4×6×162×100=1.92M_A = \dfrac{4\times6\times16}{2\times100} = 1.92 (hogging).

Ordinates (2 m interval; values shown as moments in the sagging-positive convention)

x from A (m)0246810
MAM_A0-1.44-1.92-1.68-0.960

ILD shape





**--------------------------------------------***
  **                                     *****
    ****                            *****
        *****                *******
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^                                               ^

The ILD is entirely hogging, zero at A and B, with a maximum −1.92-1.92 at about x=4.2x = 4.2 m (0.42L0.42L).

✓ Answer checked by Claude Opus 5.5 (high effort)

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