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Demand of new municipality 2016, 45,000 pop

Short answer

Design population in 2038 is 62,440. Average daily demand is 8,483 m3/day or 98.2 l/s; fire demand is 562 l/s with about 4,050 m3 reserve; distribution design flow is about 739 l/s.

Data obtained from a baseline survey of a newly formed municipality in year 2016 A.D. are as follows. Population = 45,000, No. of day scholar students in school = 9500, No. of big animals = 8000, No. of small animals = 15000. There are twenty offices, two hospital with total 50 beds. Calculate the water demand of that municipality in design year with base period of 2 years and design period of 20 years. Assume the population growth rate of the community is 1.5% per annum and fire fighting as per National Board of fire under writers.

Survey year 2016; base period 2 years and design period 20 years give the design year 2038, so n=22n = 22 years after the survey.

Design population

P2038=45,000×(1.015)22=62,440P_{2038} = 45{,}000\times(1.015)^{22} = 62{,}440

Water demand

Assumed unit rates for a municipality: domestic 110 lpcd; day scholar 5 l/d; big animal 45 l/d; small animal 5 l/d; office staff 45 l/d (10 staff per office); hospital 340 l/bed/d (IS 1172); losses 15%.

DemandQuantityRateDemand (l/day)
Domestic (110 lpcd)62,440110 l/c/d6,868,440
Day scholars9,5005 l/c/d47,500
Big animals8,00045 l/d360,000
Small animals15,0005 l/d75,000
Offices (10 staff each)20045 l/staff9,000
Hospitals (50 beds)50340 l/bed/d17,000
Net demand7,376,940

Losses and wastage =15%= 15\% of net demand =1,106,541= 1{,}106{,}541 l/day

Qavg=7,376,940+1,106,541=8,483,481 l/day=8,483.48 m3/day=98.19 l/sQ_{avg} = 7{,}376{,}940 + 1{,}106{,}541 = 8{,}483{,}481\ \text{l/day} = 8{,}483.48\ \mathrm{m^3/day} = 98.19\ \text{l/s}

Fire demand (National Board of Fire Underwriters formula)

P=62.44P = 62.44 thousand.

Qf=4637P (1−0.01P) l/min=4637×7.902×(1−0.0790)=33,746 l/min=562.4 l/s\begin{aligned} Q_f &= 4637\sqrt P\,(1-0.01\sqrt P)\ \text{l/min}\\ &= 4637\times7.902\times(1-0.0790) = 33{,}746\ \text{l/min} = 562.4\ \text{l/s} \end{aligned}

For a fire lasting 2 hours, the volume is Qf×120=4,050 m3Q_f\times120 = 4{,}050\ \mathrm{m^3}. This volume is kept as fire reserve in the service reservoir; it is not added to the average daily demand, because fire flow is an occasional rate, not a daily consumption.

Design flow with fire

The distribution system is checked for the larger of:

  • Maximum day demand + fire flow =1.8×98.19+562.4=176.7+562.4=739.1= 1.8\times98.19 + 562.4 = 176.7 + 562.4 = 739.1 l/s
  • Peak hour demand =2.7×98.19=265.1= 2.7\times98.19 = 265.1 l/s

So the mains are designed for about 739 l/s.

Answer: Design population = 62,440; average daily demand = 8,483 m3^3/day (98.2 l/s); fire demand = 33,746 l/min (562 l/s), with a 2-hour fire reserve of about 4,050 m3^3 in storage; design flow for the distribution system (maximum day + fire) ≈\approx 739 l/s.

✓ Answer checked by Claude Opus 5.5 (high effort)

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