Skip to main content

Theory of settlement; Stoke's law

Short answer

Stokes' law: v_s = g(S_s-1)d^2/(18ν) for discrete spherical particles at Re<1. It applies to laminar settling of non-flocculent particles without hindrance. Temperature effect: kinematic viscosity ν = 0.01775/(1+0.0337T+0.000221T²) cm²/s; settling at 20°C is about 1.3 times faster than at 10°C, so design uses the lowest water temperature.

Explain briefly the theory of settlement of discrete particles through quiescent liquids (derive Stoke's law and state the conditions under which it is suitable for design of a sedimentation tank). How do you modify the theory to consider the temperature effect?

Theory of settlement of discrete particles

A discrete particle is a particle that keeps its size, shape and weight while settling (e.g. sand, silt). In a quiescent liquid, it first accelerates under gravity, then very quickly reaches a terminal (settling) velocity when the net downward force is balanced by drag.

Stokes' law

For a spherical particle falling freely at constant (terminal) velocity vsv_s, the weight minus buoyancy equals the fluid drag.

Net weight=πd36(ρs−ρ) gDrag (viscous, Re<1)=3πμd vs\begin{aligned} \text{Net weight} &= \frac{\pi d^3}{6}(\rho_s-\rho)\,g \\ \text{Drag (viscous, } Re<1) &= 3\pi\mu d\,v_s \end{aligned}

Equating the two:

vs=g (ρs−ρ) d218 μ=g (Ss−1) d218 νv_s = \frac{g\,(\rho_s-\rho)\,d^2}{18\,\mu} = \frac{g\,(S_s-1)\,d^2}{18\,\nu}

where dd = particle diameter, SsS_s = specific gravity of the particle, ν=μ/ρ\nu=\mu/\rho = kinematic viscosity.

Conditions of application in design

  • The particle must be spherical, discrete (non-flocculent) and settle freely without being hindered by neighbours.
  • The flow around it must be laminar, with Reynolds number Re=vsdν<1Re=\dfrac{v_s d}{\nu}<1 (roughly particle diameter below about 0.1 mm for silt of Ss=2.65S_s=2.65).
  • The liquid is at rest or flows at very low velocity (no turbulence, no short-circuiting).
  • For larger particles (1<Re<10001<Re<1000) the drag coefficient is taken as Cd=24Re+3Re+0.34C_d=\dfrac{24}{Re}+\dfrac{3}{\sqrt{Re}}+0.34 and vs=4g(Ss−1)d3Cdv_s=\sqrt{\dfrac{4g(S_s-1)d}{3C_d}} is found by trial. For Re>1000Re>1000, vs=1.8gd(Ss−1)v_s=1.8\sqrt{g d (S_s-1)} (Newton).

In an ideal rectangular tank the removal depends only on the overflow rate v0=Q/A=H/tv_0=Q/A=H/t: a particle with vs≥v0v_s\ge v_0 is entirely removed.

Effect of temperature

Temperature changes the viscosity, and so the settling velocity (vs∝1/νv_s\propto 1/\nu). The kinematic viscosity at temperature TT (°C) can be calculated from

ν=0.017751+0.0337 T+0.000221 T2 cm2/s\nu = \frac{0.01775}{1+0.0337\,T+0.000221\,T^2}\ \text{cm}^2/\text{s}

and for the same particle:

vs,T2vs,T1=νT1νT2\frac{v_{s,T_2}}{v_{s,T_1}} = \frac{\nu_{T_1}}{\nu_{T_2}}

Typical values:

Temp (°C)1015202125
ν\nu (cm2^2/s)0.013060.011390.010070.009780.00893

Hence the settling velocity at 20 °C is about 1.3 times that at 10 °C. For design, the lowest expected temperature is used, so the tank is also effective in warm weather.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Water Supply Engineering chapter 6 questions →