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Mortar and estimation of mortar requirement

Short answer

Mortar is a workable paste of binder, sand and water for bonding masonry. Estimation: subtract solid brick volume from masonry volume to get wet mortar; dry volume = wet × 1.27. For 1:n mix, cement = dry volume/(1+n) and sand = n × dry volume/(1+n).

What is mortar? Describe the estimation of mortar requirement.

Mortar

Mortar is a paste of binding material (cement or lime), fine aggregate (sand) and water; it is used to join bricks or stones, fill joints and plaster surfaces. Common types are cement mortar (1:3 to 1:6), lime mortar, cement-lime (gauged) mortar and mud mortar.

Estimation of mortar requirement

The mortar needed depends on the volume of masonry and the volume of units in it.

  1. Find the volume of brickwork VV (m³).
  2. Find the size of a brick with mortar, e.g. (240+10)×(115+10)×(57+10)(240+10)\times(115+10)\times(57+10) mm, and the number of bricks N=V/volume of one brick with mortarN = V/\text{volume of one brick with mortar}.
  3. Volume of bricks without mortar =N×0.24×0.115×0.057= N \times 0.24 \times 0.115 \times 0.057.
  4. Wet volume of mortar =V−= V - volume of bricks.
  5. Dry volume == wet volume ×\times 1.27 (to account for voids in sand, shrinkage and wastage).
  6. Divide by the mix ratio 1:n1:n: cement =dry volume1+n= \dfrac{\text{dry volume}}{1+n}, sand =n1+n×dry volume= \dfrac{n}{1+n}\times\text{dry volume}.
  7. Convert cement to bags: 1 bag (50 kg) =0.0347= 0.0347 m³.

Worked example (10 m³ brickwork, 1:6)

  • Bricks =10/(0.25×0.125×0.067)≈4777= 10/(0.25\times0.125\times0.067) \approx 4777.
  • Brick volume =4777×0.0015732=7.515= 4777 \times 0.0015732 = 7.515 m³.
  • Wet mortar =10−7.515=2.485= 10 - 7.515 = 2.485 m³; dry =2.485×1.27=3.156= 2.485 \times 1.27 = 3.156 m³.
  • Cement =3.156/7=0.451= 3.156/7 = 0.451 m³ (≈\approx 13 bags); sand =3.156×6/7=2.705= 3.156 \times 6/7 = 2.705 m³.

For plaster: mortar volume == area ×\times thickness ×\times 1.27 (dry).

✓ Answer checked by Claude Opus 5.5 (high effort)

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