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Double room: excavation, CRS, brick, plaster

Short answer

Using an assumed double-room layout, centre-line method gives excavation 36.30 m³, crushed rubble stone masonry 10.54 m³, first-class brickwork 21.70 m³, and 12 mm inner plaster 80.46 m².

Calculate the quantities from the given building drawings: Fig. 1(a, b) a) Earthwork in excavation b) Crushed rubble stone masonry c) 1st class brick work in super structure d) 12 mm plastering work 1:4 for inner wall Following are the double room building estimation specifications:

  • In foundation cement concrete M25 is used.
  • CRS wall is used in the foundation for the base of the brick wall.
  • Plinth beam size is 400 mm × 600 mm in cement concrete M25.
  • Damp-proof course 25 mm thick is applied.
  • In superstructure 1st class brickwork is in 1:4 cement mortar and thickness 300 mm.
  • Doors D, size 1.2 m × 2.1 m
  • Windows W, size 1 m × 1.5 m
  • Shelves S-1 m × 1.5 m [Fig. 1(a, b) not included in the scanned paper]

Fig. 1 is not available, so an assumed double-room building is used with the given specifications.

Assumed data

  • Two rooms side by side, each 4.0 m × 3.5 m clear; all walls 300 mm (as stated). Outside size = (2 × 4.0 + 3 × 0.3) × (3.5 + 2 × 0.3) = 8.90 × 4.10 m.
  • Centre-line length of outer walls = 2[(8.90 − 0.3) + (4.10 − 0.3)] = 24.80 m. The partition is 3.5 + 0.3 = 3.80 m between the centre lines of the outer walls; at each of its two T-junctions it is shortened by half the width of the outer-wall item, so its length is 3.80 − 1.10 = 2.70 m for the trench, 3.80 − 0.50 = 3.30 m for the CRS and 3.80 − 0.30 = 3.50 m for the brickwork.
  • Foundation: trench 1.10 m wide, 1.20 m deep; CC M25 bed 0.30 m; CRS wall 0.50 m wide, 0.75 m high from top of bed to bottom of plinth beam (0.15 m below GL); plinth beam 400 × 600 mm (not asked).
  • Superstructure 3.0 m high above plinth beam; D 1.2 × 2.1 (2 nos.), W 1.0 × 1.5 (3 nos.), shelf recess S 1.0 × 1.5 × 0.15 m deep (2 nos.). Plaster 12 mm 1:4.

a) Earthwork in excavation

ItemNo.L (m)B (m)H/D (m)Qty (m³)
Trench, outer walls124.8001.1001.20032.736
Trench, partition (3.80 − 1.10)12.7001.1001.2003.564
Total36.300

b) Crushed rubble stone masonry

ItemNo.L (m)B (m)H/D (m)Qty (m³)
CRS masonry, outer walls, 0.50 wide × 0.75 high124.8000.5000.7509.300
CRS masonry, partition (3.80 − 0.50)13.3000.5000.7501.238
Total10.538

(For reference, M25 concrete bed = (24.80 + 2.70) × 1.10 × 0.30 = 9.08 m³.)

c) 1st class brick work in superstructure (1:4)

ItemNo.L (m)B (m)H/D (m)Qty (m³)
Wall 0.30 × 3.0 above plinth beam (24.80 + 3.50)128.3000.3003.00025.470
Deduct doors D 1.2 × 2.1 (2 nos.)-21.2000.3002.100-1.512
Deduct windows W 1.0 × 1.5 (3 nos.)-31.0000.3001.500-1.350
Deduct shelves S 1.0 × 1.5 × 0.15 recess (2 nos.)-21.0000.1501.500-0.450
Deduct lintels over doors-21.6000.3000.150-0.144
Deduct lintels over windows and shelves-51.4000.3000.150-0.315
Total21.699

d) 12 mm plastering, 1:4, inner wall

ItemNo.L (m)B (m)H/D (m)Qty (m²)
Inside walls, both rooms 2 × 2(4.0+3.5) × 3.0130.0003.000–90.000
Deduct doors (one inside face each)-21.2002.100–-5.040
Deduct windows-31.0001.500–-4.500
Total80.460

Answer: Excavation 36.30 m³; CRS 10.54 m³; brickwork 21.70 m³; plaster 80.46 m² (assumed layout).

✓ Answer checked by Claude Opus 5.5 (high effort)

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