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Capture effect; gain parameter of DSB-FC envelope detection

Short answer

Capture effect is the FM receiver property that the stronger of two nearly identical frequency signals is reproduced and the weaker is almost completely suppressed. The DSB-FC envelope-detection gain parameter is γ = k_a²P/(1 + k_a²P); for tone modulation γ = μ²/(2 + μ²). At 100% modulation (μ = 1) γ = 1/3.

What is capture effect? Calculate the gain parameter in DSB-FC with envelope detection.

Capture effect

Capture effect is the property of an FM receiver whereby, when two FM signals on (nearly) the same frequency are received, the stronger one is reproduced and the weaker one is almost completely suppressed. The limiter and discriminator respond to the dominant signal's phase, so the weaker signal appears only as small noise. If the two strengths are nearly equal (within about 1 dB), the receiver may switch between them. AM receivers do not show this; both signals are heard together.

Gain parameter (figure of merit) of DSB-FC with envelope detection

Assumptions: message m(t)m(t) of bandwidth WW and power P=m2(t)‾P = \overline{m^2(t)}; white noise of PSD N0/2N_0/2; IF filter bandwidth 2W2W; high carrier-to-noise ratio.

Transmitted signal: s(t)=Ac[1+kam(t)]cos⁡ωcts(t) = A_c[1 + k_a m(t)]\cos\omega_c t

Channel (input) SNR. Signal power =Ac2(1+ka2P)2= \dfrac{A_c^2(1+k_a^2P)}{2}; noise power in bandwidth WW (reference baseband) =WN0= WN_0:

(SNR)C=Ac2(1+ka2P)2WN0(SNR)_C = \frac{A_c^2(1+k_a^2P)}{2WN_0}

Received signal with narrowband noise

x(t)=[Ac+Ackam(t)+nI(t)]cos⁡ωct−nQ(t)sin⁡ωct\begin{aligned} x(t) &= [A_c + A_ck_am(t) + n_I(t)]\cos\omega_c t - n_Q(t)\sin\omega_c t \end{aligned}

where nI,nQn_I, n_Q each have power 2WN02WN_0. The envelope is

y(t)=[Ac+Ackam(t)+nI(t)]2+nQ2(t)y(t) = \sqrt{[A_c + A_ck_am(t) + n_I(t)]^2 + n_Q^2(t)}

For high SNR, Ac[1+kam(t)]≫∣nQ(t)∣A_c[1+k_am(t)] \gg |n_Q(t)|, so

y(t)≈Ac+Ackam(t)+nI(t)y(t) \approx A_c + A_ck_am(t) + n_I(t)

The DC term AcA_c is removed by a blocking capacitor.

Output SNR

(SNR)O=Ac2ka2P2WN0(SNR)_O = \frac{A_c^2k_a^2P}{2WN_0}

Figure of merit (gain parameter)

γ=(SNR)O(SNR)C=ka2P1+ka2P\gamma = \frac{(SNR)_O}{(SNR)_C} = \frac{k_a^2P}{1+k_a^2P}

which is always less than 1.

Single tone m(t)=Amcos⁡ωmtm(t) = A_m\cos\omega_m t, μ=kaAm\mu = k_aA_m: ka2P=μ2/2k_a^2P = \mu^2/2, so

γ=μ22+μ2\gamma = \frac{\mu^2}{2+\mu^2}

For 100 % modulation (μ=1\mu = 1): γ=1/3\gamma = 1/3. So DSB-FC with envelope detection needs three times (4.77 dB) more transmitted power than DSB-SC/SSB with coherent detection (γ=1\gamma = 1) for the same output SNR, because much power goes into the carrier.

Low SNR: when noise dominates the carrier, the message is no longer separable in the envelope and output SNR falls sharply: this is the threshold effect of the envelope detector.

✓ Answer checked by Claude Opus 5.5 (high effort)

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