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Envelope detector; can it demodulate DSB-SC?

Short answer

An envelope detector charges a capacitor to the carrier peaks and discharges slowly, following the AM envelope. It cannot demodulate DSB-SC because the envelope is |m(t)|, producing a rectified and distorted output; DSB-SC requires coherent detection.

Explain the process of demodulation of AM wave using envelope detector. Does envelope detector demodulate DSB-SC AM wave? Explain.

The envelope detector is a simple non-coherent demodulator whose output follows the envelope of the AM wave. Since standard AM has envelope Ac[1+kam(t)]A_c[1+k_am(t)], which is a shifted copy of m(t)m(t), it recovers the message without any local carrier.

Circuit

        D
 o---->|---+------+--------o
           |      |
 AM in     C      R      vo(t) ~ envelope
           |      |
 o---------+------+--------o

Working

  1. Positive half cycle: when the input exceeds the capacitor voltage, the diode conducts and CC charges quickly to the peak of the carrier through the small source resistance (RsC≪1/fcR_sC\ll1/f_c).
  2. Between peaks: when the input falls below the capacitor voltage, the diode becomes reverse-biased and CC discharges slowly through RR.
  3. On the next peak the diode conducts again and recharges CC. Thus the capacitor voltage follows the peaks of the carrier, i.e. the envelope, with a small ripple at fcf_c.
  4. A DC-blocking capacitor removes the DC (AcA_c) and a small RC low-pass filter removes ripple, giving m(t)m(t).

Time constant condition:

1fc≪RC≪1W\frac{1}{f_c}\ll RC\ll\frac{1}{W}
  • If RCRC is too small, the output follows the carrier cycles (large ripple).
  • If RCRC is too large, the capacitor cannot follow a falling envelope (diagonal clipping); for a tone with index μ\mu we need RC≤1−μ2μ ωmRC\le\frac{\sqrt{1-\mu^2}}{\mu\,\omega_m}.
 AM wave       envelope      detector output
  /\  /\/\       ___           ___
 /  \/    \/\   /   \  __     /   \  __ (small ripple)

Requirements: μ≤1\mu\le1 (no over-modulation) and fc≫Wf_c\gg W.

Can an envelope detector demodulate DSB-SC?

No. A DSB-SC wave is s(t)=Acm(t)cos⁡ωcts(t)=A_cm(t)\cos\omega_ct. Its envelope is Ac∣m(t)∣A_c\lvert m(t)\rvert, not m(t)m(t). Whenever m(t)m(t) becomes negative, the carrier phase reverses by 180°180° but the envelope stays positive, so the detector output is the rectified message ∣m(t)∣\lvert m(t)\rvert, which is badly distorted. For example, a tone cos⁡ωmt\cos\omega_mt comes out as ∣cos⁡ωmt∣\lvert\cos\omega_mt\rvert, which contains 2fm2f_m and higher harmonics. DSB-SC therefore needs coherent (synchronous) detection, using a carrier recovered by a Costas loop or squaring loop. (Envelope detection would only work if a large carrier were re-inserted, which converts it back to standard AM.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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