- 2076 Bhadra (CS I) · 2+6 marks
Compare DSB-AM, DSB-SC, SSB, VSB; SSB by phase discrimination
Short answer
DSB-AM bandwidth 2W, efficiency ≤33%; DSB-SC 2W, 100% efficient; SSB bandwidth W, 100% efficient; VSB slightly >W. Phase-shift method for SSB: two balanced modulators fed with m(t) and its Hilbert transform m̂(t) using 90° phase-shifted carriers; summing or differencing outputs gives LSB or USB.
Compare the performance of DSB-AM, DSB-SC, SSB-AM, VSB. Describe the process of generation of SSB-AM wave using phase discrimination method.
Performance comparison
| Parameter | DSB-AM (FC) | DSB-SC | SSB | VSB |
|---|---|---|---|---|
| Bandwidth | (slightly > ) | |||
| Carrier | Sent | Suppressed | Suppressed | Suppressed or sent (TV) |
| Power efficiency | ≤ 33.3% | 100% | 100% | ~100% (without carrier) |
| Detection | Envelope | Coherent | Coherent | Coherent or envelope (with carrier) |
| Generation | Simple | Simple | Complex | Moderate |
| Low-freq/DC message | Yes | Yes | Difficult | Yes |
| Receiver cost | Lowest | High | Highest | Moderate |
| Use | AM broadcast | Stereo, QAM | HF voice | TV video |
SSB generation by phase discrimination (phase-shift) method
+-->[Balanced mod 1]--v1--+
| ^ |
m(t) ----+ Ac cos wc t v
| | (+/-) ---> SSB
| [-90 deg] ^
| | |
+-[-90]->[Balanced mod 2]-v2
m^(t) Ac sin wc t
- Balanced modulator 1 multiplies with .
- A wideband phase shifter (Hilbert transformer) produces ; balanced modulator 2 multiplies it with the shifted carrier .
- The outputs are subtracted for USB or added for LSB.
Derivation with :
General: .
Advantages: no sharp filter; works at any carrier frequency; sideband switched by changing sign. Disadvantage: the shifter must be exact over the entire audio band, otherwise the unwanted sideband is only partly cancelled.
✓ Answer checked by Claude Opus 5.5 (high effort)
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