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Noise performance of DSB-AM, DSB-SC and SSB-SC

Short answer

DSB-SC (FOM 1, gain 2) and SSB-SC (FOM 1, gain 1) give identical output SNR for equal transmitted power; SSB uses half the bandwidth. DSB-FC (AM) wastes power in the carrier, resulting in a figure of merit less than 1, e.g., 1/3 for 100% tone modulation.

With necessary derivation, compare noise performance of DSB-AM, DSB-SC, SSB-SC.

Receiver model. The received signal s(t)s(t) plus white noise (N0/2N_0/2) passes through a band-pass (IF) filter of bandwidth BTB_T, then a demodulator and a low-pass filter of bandwidth WW (message bandwidth).

 s(t)  +   +-------+    +-------+   +-----+
 ---->(+)-->|  BPF  |--->| demod |-->| LPF |--> y(t)
       ^    |  B_T  |    |       |   |  W  |
      w(t)  +-------+    +-------+   +-----+

The filtered noise is narrowband and is written in in-phase/quadrature form

n(t)=nc(t)cos⁡ωct−ns(t)sin⁡ωctn(t)=n_c(t)\cos\omega_ct-n_s(t)\sin\omega_ct

where ncn_c and nsn_s are low-pass, each with the same power as n(t)n(t): nc2‾=ns2‾=n2‾=N0BT\overline{n_c^2}=\overline{n_s^2}=\overline{n^2}=N_0B_T.

Definitions. Message power P=m2(t)‾P=\overline{m^2(t)}.

  • Input SNR SNRi=received signal powernoise power in BT\text{SNR}_i=\dfrac{\text{received signal power}}{\text{noise power in } B_T}
  • Output SNR SNRo=message power at outputnoise power at output\text{SNR}_o=\dfrac{\text{message power at output}}{\text{noise power at output}}
  • Detection gain γd=SNRoSNRi\gamma_d=\dfrac{\text{SNR}_o}{\text{SNR}_i}; figure of merit =SNRoSNRref=\dfrac{\text{SNR}_o}{\text{SNR}_{ref}}, where SNRref\text{SNR}_{ref} is the channel SNR measured in the message band WW (baseband reference). Both show how much the demodulator improves or worsens SNR.

DSB-FC (conventional AM). s(t)=Ac[1+kam(t)]cos⁡ωcts(t)=A_c[1+k_am(t)]\cos\omega_ct, BT=2WB_T=2W. (Coherent and envelope detection give the same result at high SNR.)

  • Signal power =Ac22(1+ka2P)=\frac{A_c^2}{2}(1+k_a^2P); noise in 2W2W =2N0W=2N_0W:
SNRi=Ac2(1+ka2P)4N0W\text{SNR}_i=\frac{A_c^2(1+k_a^2P)}{4N_0W}
  • Coherent detection (or envelope detection at high SNR) and DC blocking:
y(t)=Ac2kam(t)+12nc(t) ⇒ SNRo=Ac2ka2P/42N0W/4=Ac2ka2P2N0Wy(t)=\frac{A_c}{2}k_am(t)+\frac12n_c(t)\ \Rightarrow\ \text{SNR}_o=\frac{A_c^2k_a^2P/4}{2N_0W/4}=\frac{A_c^2k_a^2P}{2N_0W} γDSB-FC=SNRoSNRi=2ka2P1+ka2P,FOM=ka2P1+ka2P\gamma_{DSB\text{-}FC}=\frac{\text{SNR}_o}{\text{SNR}_i}=\frac{2k_a^2P}{1+k_a^2P},\qquad \text{FOM}=\frac{k_a^2P}{1+k_a^2P}

The carrier uses power but carries no information, so the gain is reduced.

Single tone, 100% modulation. m(t)=Amcos⁡ωmtm(t)=A_m\cos\omega_mt, μ=kaAm=1\mu=k_aA_m=1, so ka2P=μ22=12k_a^2P=\frac{\mu^2}{2}=\frac12:

γDSB-FC=2(μ2/2)1+μ2/2=2μ22+μ2=23≈0.667FOM=μ22+μ2=13\begin{aligned} \gamma_{DSB\text{-}FC} &= \frac{2(\mu^2/2)}{1+\mu^2/2}=\frac{2\mu^2}{2+\mu^2}=\frac{2}{3}\approx0.667 \\ \text{FOM} &= \frac{\mu^2}{2+\mu^2}=\frac13 \end{aligned}

DSB-SC (coherent detection). s(t)=Acm(t)cos⁡ωcts(t)=A_cm(t)\cos\omega_ct, BT=2WB_T=2W.

  • Signal power =Ac2P2=\frac{A_c^2P}{2}; noise in 2W2W =2N0W=2N_0W, so SNRi=Ac2P4N0W\text{SNR}_i=\dfrac{A_c^2P}{4N_0W}.
  • Multiply x(t)=s(t)+n(t)x(t)=s(t)+n(t) by cos⁡ωct\cos\omega_ct and low-pass filter:
y(t)=Ac2m(t)+12nc(t)y(t)=\frac{A_c}{2}m(t)+\frac12n_c(t)
  • SNRo=Ac2P/42N0W/4=Ac2P2N0W\text{SNR}_o=\dfrac{A_c^2P/4}{2N_0W/4}=\dfrac{A_c^2P}{2N_0W}
γDSB-SC=SNRoSNRi=2\gamma_{DSB\text{-}SC}=\frac{\text{SNR}_o}{\text{SNR}_i}=2

The quadrature noise nsn_s is rejected by coherent detection, giving a 3 dB gain. With baseband reference SNRref=Ac2P2N0W\text{SNR}_{ref}=\frac{A_c^2P}{2N_0W}, figure of merit =1=1.

SSB-SC (coherent detection). s(t)=Ac2[m(t)cos⁡ωct∓m^(t)sin⁡ωct]s(t)=\frac{A_c}{2}[m(t)\cos\omega_ct\mp\hat m(t)\sin\omega_ct], BT=WB_T=W.

  • Signal power =Ac24⋅P+P2=Ac2P4=\frac{A_c^2}{4}\cdot\frac{P+P}{2}=\frac{A_c^2P}{4} (since m^2‾=P\overline{\hat m^2}=P); noise in WW =N0W=N_0W, so SNRi=Ac2P4N0W\text{SNR}_i=\dfrac{A_c^2P}{4N_0W}.
  • Multiply by cos⁡ωct\cos\omega_ct and low-pass filter:
y(t)=Ac4m(t)+12nc(t)y(t)=\frac{A_c}{4}m(t)+\frac12n_c(t)
  • Signal power Ac2P16\frac{A_c^2P}{16}, noise power N0W4\frac{N_0W}{4}, so SNRo=Ac2P4N0W\text{SNR}_o=\dfrac{A_c^2P}{4N_0W}
γSSB=SNRoSNRi=1\gamma_{SSB}=\frac{\text{SNR}_o}{\text{SNR}_i}=1

With baseband reference (SNRref=Ac2P4N0W\text{SNR}_{ref}=\frac{A_c^2P}{4N_0W}, same transmitted power), figure of merit =1=1.

Comparison:

ParameterDSB-FC (AM)DSB-SCSSB-SC
Transmission bandwidth BTB_T2W2W2W2WWW
DetectorEnvelope or coherentCoherentCoherent
Detection gain SNRo/SNRi\text{SNR}_o/\text{SNR}_i2ka2P1+ka2P\frac{2k_a^2P}{1+k_a^2P} (=23=\frac23 at μ=1\mu=1)21
Figure of merit (baseband ref.)ka2P1+ka2P\frac{k_a^2P}{1+k_a^2P} (=13=\frac13 at μ=1\mu=1)11
Threshold effectYes (envelope detector)NoNo
Power wasted in carrierYes (at least 1/2; 2/3 for a 100% tone)NoNo

Conclusions: for the same transmitted power and noise PSD, DSB-SC and SSB give the same output SNR (equal to baseband); DSB-SC's detection gain of 2 is offset by its double noise bandwidth. SSB achieves this in half the bandwidth. DSB-FC is at least 3 dB worse (since ka2P≤1k_a^2P\le1 gives FOM ≤12\le\frac12, with equality only for a 100% square wave) and 4.77 dB worse (a factor of 3) for 100% single-tone modulation, because the carrier carries no information; its advantage is that it allows a cheap envelope detector.

✓ Answer checked by Claude Opus 5.5 (high effort)

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