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Envelope detector; why not for DSB-SC and SSB

Short answer

Envelope detector tracks the peaks of AM wave, requiring μ≤1 to avoid distortion. DSB-SC envelope is |m(t)| because carrier phase reverses when m(t) negative, causing rectified output. SSB envelope is constant for a tone and not proportional to m(t). Both need synchronous detection.

Describe how envelope detector can be used for demodulation of standard AM wave. Explain why DSB-SC and SSB can not be demodulated using envelope detector.

An envelope detector is a diode–RC circuit that tracks the peaks (envelope) of a standard AM wave Ac[1+μm(t)]cos⁡ωctA_c[1+\mu m(t)]\cos\omega_ct, giving Ac[1+μm(t)]A_c[1+\mu m(t)] and hence m(t)m(t) after removing DC.

Circuit

        D
 o----->|-----+--------+-----o
 AM           |        |
 input   C  ===       > RL   v_o
              |        >
 o------------+--------+-----o

Operation

  1. Charging: in each positive carrier half cycle, when the input is above the capacitor voltage, the diode conducts and CC charges through the small source resistance RsR_s almost to the peak.
  2. Discharging: once the input falls below the capacitor voltage, the diode is cut off and CC discharges slowly through RLR_L.
  3. Repeating every carrier cycle, the capacitor voltage follows the envelope with a small saw-tooth ripple at fcf_c.
  4. A low-pass RC filter smooths the ripple and a blocking capacitor removes the DC term AcA_c, leaving μAcm(t)\mu A_c m(t).
 AM in:   /\/\/\  /\/\/\
         /\/\/\/\/\/\/\/\  (peaks follow m)
 Out:      ___      ___
         _/   \____/   \_  (envelope)

Design conditions

  • RsC≪1/fcR_sC \ll 1/f_c (fast charge)
  • 1/fc≪RLC≪1/W1/f_c \ll R_LC \ll 1/W (small ripple, yet follows the message)
  • For a tone, to avoid diagonal clipping: RLC≤1−μ2μωmR_LC \le \dfrac{\sqrt{1-\mu^2}}{\mu\omega_m}
  • μ≤1\mu \le 1 (no over-modulation)

Why DSB-SC cannot be envelope detected

sDSB(t)=Acm(t)cos⁡ωcts_{DSB}(t) = A_cm(t)\cos\omega_ct. Its envelope is Ac∣m(t)∣A_c|m(t)|, not m(t)m(t). When m(t)m(t) goes negative, the carrier phase reverses by 180°, but the peaks stay positive. The envelope detector outputs ∣m(t)∣|m(t)|, a rectified (full-wave) copy of the message, which is badly distorted.

 m(t):    /\      /\         |m(t)|:  /\  /\  /\
        _/  \    /  \_    ->         /  \/  \/  \
             \__/

Example: for m(t)=cos⁡ωmtm(t) = \cos\omega_mt the output contains ∣cos⁡ωmt∣|\cos\omega_mt|, which has components at 0,2fm,4fm,…0, 2f_m, 4f_m, \dots and none at fmf_m.

Why SSB cannot be envelope detected

sSSB(t)=Ac2[m(t)cos⁡ωct∓m^(t)sin⁡ωct]s_{SSB}(t) = \frac{A_c}{2}[m(t)\cos\omega_ct \mp \hat m(t)\sin\omega_ct]. Its envelope is

a(t)=Ac2m2(t)+m^2(t)a(t) = \frac{A_c}{2}\sqrt{m^2(t) + \hat m^2(t)}

which is not proportional to m(t)m(t). For a single tone m=Amcos⁡ωmtm = A_m\cos\omega_mt, m^=Amsin⁡ωmt\hat m = A_m\sin\omega_mt, so the envelope is constant, AcAm/2A_cA_m/2: the detector gives only DC and the message is lost completely.

Both DSB-SC and SSB therefore need coherent (synchronous) detection, or a large carrier must be added at the receiver so that the envelope again follows m(t)m(t).

✓ Answer checked by Claude Opus 5.5 (high effort)

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