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Fourier transform properties; Rayleigh energy theorem

Short answer

Four properties: linearity, time shift, time scaling, and modulation. Rayleigh's energy theorem states that total signal energy equals ∫|g(t)|² dt = ∫|G(f)|² df, derived by substituting g*(t) with the inverse transform of G*(f) and swapping integrals.

State any four properties of the Fourier Transform. Derive the expression for the Rayleigh Energy Theorem.

The Fourier transform pair is G(f)=∫−∞∞g(t)e−j2πftdtG(f)=\int_{-\infty}^{\infty} g(t)e^{-j2\pi ft}dt and g(t)=∫−∞∞G(f)ej2πftdfg(t)=\int_{-\infty}^{\infty} G(f)e^{j2\pi ft}df, written g(t)↔G(f)g(t)\leftrightarrow G(f).

Four properties of the Fourier transform

PropertyTime domainFrequency domain
Linearityag1(t)+bg2(t)a g_1(t)+b g_2(t)aG1(f)+bG2(f)aG_1(f)+bG_2(f)
Time shiftingg(t−t0)g(t-t_0)G(f)e−j2πft0G(f)e^{-j2\pi f t_0}
Time scalingg(at)g(at)1∣a∣G(fa)\frac{1}{\lvert a\rvert}G\left(\frac{f}{a}\right)
Modulation (frequency shift)g(t)cos⁡2πfctg(t)\cos 2\pi f_c t12[G(f−fc)+G(f+fc)]\frac{1}{2}[G(f-f_c)+G(f+f_c)]
Convolutiong1(t)∗g2(t)g_1(t)*g_2(t)G1(f)G2(f)G_1(f)G_2(f)
DualityG(t)G(t)g(−f)g(-f)
  • Linearity: the transform of a weighted sum is the weighted sum of the transforms.
  • Time shifting: a delay changes only the phase spectrum (linear phase), not the amplitude spectrum.
  • Scaling: compressing a signal in time expands its spectrum, and vice versa.
  • Modulation: multiplying by a carrier shifts the spectrum to ±fc\pm f_c; this is the basis of AM.

Rayleigh energy theorem

Statement: the total energy of an energy signal is the same whether calculated in the time domain or in the frequency domain:

E=∫−∞∞∣g(t)∣2dt=∫−∞∞∣G(f)∣2dfE=\int_{-\infty}^{\infty}\lvert g(t)\rvert^2dt=\int_{-\infty}^{\infty}\lvert G(f)\rvert^2df

Derivation: write ∣g(t)∣2=g(t)g∗(t)\lvert g(t)\rvert^2=g(t)g^*(t) and express g∗(t)g^*(t) by the inverse transform:

g∗(t)=[∫−∞∞G(f)ej2πftdf]∗=∫−∞∞G∗(f)e−j2πftdfg^*(t)=\left[\int_{-\infty}^{\infty}G(f)e^{j2\pi ft}df\right]^*=\int_{-\infty}^{\infty}G^*(f)e^{-j2\pi ft}df

Substitute into the energy integral and change the order of integration:

E=∫−∞∞g(t)[∫−∞∞G∗(f)e−j2πftdf]dt=∫−∞∞G∗(f)[∫−∞∞g(t)e−j2πftdt]df=∫−∞∞G∗(f) G(f) df=∫−∞∞∣G(f)∣2df\begin{aligned} E&=\int_{-\infty}^{\infty}g(t)\left[\int_{-\infty}^{\infty}G^*(f)e^{-j2\pi ft}df\right]dt\\ &=\int_{-\infty}^{\infty}G^*(f)\left[\int_{-\infty}^{\infty}g(t)e^{-j2\pi ft}dt\right]df\\ &=\int_{-\infty}^{\infty}G^*(f)\,G(f)\,df\\ &=\int_{-\infty}^{\infty}\lvert G(f)\rvert^2df \end{aligned}

The inner bracket in the second line is just G(f)G(f) by definition. Hence the theorem is proved.

Meaning: ∣G(f)∣2\lvert G(f)\rvert^2 is the energy spectral density Ψg(f)\Psi_g(f) (unit J/Hz); integrating it over all frequencies gives the total energy. Example: for g(t)=A rect(t/T)g(t)=A\,\text{rect}(t/T), time-domain energy is A2TA^2T, and integrating A2T2sinc2(fT)A^2T^2\text{sinc}^2(fT) over ff also gives A2TA^2T.

✓ Answer checked by Claude Opus 5.5 (high effort)

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