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Fourier transform property: Scaling

Short answer

The scaling property states that if g(t) ↔ G(f), then g(at) ↔ (1/|a|)G(f/a). Time compression (|a|>1) expands the spectrum in frequency with reduced amplitude, while time stretching (|a|<1) shrinks the spectrum. The 1/|a| factor preserves energy. For a=-1, time reversal gives g(-t) ↔ G(-f).

State and explain the scaling property of Fourier Transform.

Statement: if g(t)↔G(f)g(t)\leftrightarrow G(f), then for a real constant aa

g(at)↔1∣a∣G(fa)g(at)\leftrightarrow\frac{1}{\lvert a\rvert}G\left(\frac{f}{a}\right)

Explanation: if ∣a∣>1\lvert a\rvert>1 the signal is compressed in time, and its spectrum is expanded in frequency (with reduced height); if ∣a∣<1\lvert a\rvert<1 the signal is stretched and its spectrum shrinks. The factor 1/∣a∣1/\lvert a\rvert keeps the energy relation consistent. For a=−1a=-1, g(−t)↔G(−f)g(-t)\leftrightarrow G(-f) (time reversal).

Example: a rectangular pulse of width TT has spectrum T sinc(fT)T\,\text{sinc}(fT) with first null at 1/T1/T. Halving the width to T/2T/2 moves the first null to 2/T2/T, doubling the bandwidth.

Significance: this is the inverse relation between pulse duration and bandwidth: faster data (shorter pulses) needs more bandwidth. Playing a tape at double speed raises all pitches by an octave.

✓ Answer checked by Claude Opus 5.5 (high effort)

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