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PSD–autocorrelation relation; stereo FM

Short answer

By the Wiener–Khinchin theorem, power spectral density and autocorrelation function are a Fourier-transform pair: S_X(f) = ∫ R_X(τ)e^{-j2πfτ}dτ. For stereo FM, an encoder combines L+R (0–15 kHz) and L−R DSB-SC centered at 38 kHz with a 19 kHz pilot. The decoder extracts the pilot to regenerate the 38 kHz carrier, coherently detects L−R, and a matrix recovers L and R.

What is the relation between psdf and Autocorrelation function? Explain the Stereo FM encoder and decoder with spectral diagram.

Relation between PSD and autocorrelation

By the Wiener–Khinchin theorem, the power spectral density (PSD) SX(f)S_X(f) of a wide-sense stationary process and its autocorrelation function RX(τ)R_X(\tau) form a Fourier transform pair:

SX(f)=∫−∞∞RX(τ) e−j2πfτdτ,RX(τ)=∫−∞∞SX(f) ej2πfτdfS_X(f) = \int_{-\infty}^{\infty}R_X(\tau)\,e^{-j2\pi f\tau}d\tau, \qquad R_X(\tau) = \int_{-\infty}^{\infty}S_X(f)\,e^{j2\pi f\tau}df

Consequences:

  • Total average power: P=RX(0)=∫SX(f) dfP = R_X(0) = \int S_X(f)\,df.
  • SX(f)S_X(f) is real and even (because RX(τ)R_X(\tau) is real and even), and it is never negative.
  • Example: white noise R(τ)=N02δ(τ)⇔S(f)=N02R(\tau) = \frac{N_0}{2}\delta(\tau) \Leftrightarrow S(f) = \frac{N_0}{2}.

Stereo FM encoder

Stereo FM sends left (L) and right (R) channels on one carrier while staying compatible with mono receivers.

 L --+-->(+)--L+R-->[LPF]----------->( Σ )-->
     |    ^                            ^ ^  to FM
 R --|----+                            | |  mod.
     +-->(-)--L-R-->[LPF]-->[Bal.mod]--+ |
          ^ (R)                 ^ 38k    |
                  [19k osc]->[x2]        |
                      |                  |
                      +--19 kHz pilot----+
  1. Matrix forms L+RL+R and L−RL-R; both are band-limited to 15 kHz and pre-emphasized.
  2. L−RL-R DSB-SC modulates a 38 kHz sub-carrier in a balanced modulator.
  3. The 38 kHz sub-carrier comes from a 19 kHz oscillator and a doubler; a small 19 kHz pilot is also added.
  4. Composite signal:
m(t)=(L+R)+(L−R)cos⁡(2π 38k t)+Apcos⁡(2π 19k t)m(t) = (L+R) + (L-R)\cos(2\pi\,38\text{k}\,t) + A_p\cos(2\pi\,19\text{k}\,t)

Spectrum

 |  L+R      pilot    L-R DSB-SC
 |______       |    ____    ____
 |      |      |   |    |  |    |
 +------+------+---+----+--+----+---> f (kHz)
 0     15     19  23   38      53

Stereo FM decoder

FM    +->[LPF 0-15k]------------L+R--+->(+)--> 2L
demod |                              |   ^
out --+->[BPF 23-53k]-->( X )->[LPF]-+   |
      |                   ^      L-R  |  |
      |                   | 38k       +--|-->(-)--> 2R
      +->[BPF 19k]-->[ x2 ]              |
         (pilot)                  L-R ---+
  1. FM discriminator gives the composite signal.
  2. LPF (0–15 kHz) gives L+RL+R (all a mono set needs).
  3. A narrow BPF picks the 19 kHz pilot; a doubler makes a phase-locked 38 kHz carrier.
  4. BPF (23–53 kHz) selects the L−RL-R DSB-SC signal, which is coherently detected with the 38 kHz carrier and low-pass filtered.
  5. Matrix: (L+R)+(L−R)=2L(L+R)+(L-R) = 2L and (L+R)−(L−R)=2R(L+R)-(L-R) = 2R, then de-emphasis and audio amplifiers.

✓ Answer checked by Claude Opus 5.5 (high effort)

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