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Single tone DSB-FC AM in time and frequency domain

Short answer

For single-tone DSB-FC AM, time domain is s(t)=Ac[1+μ cos(2πfmt)]cos(2πfct) expanding to carrier plus upper and lower sidebands. Frequency domain has impulses at ±fc (weight Ac/2) and ±(fc±fm) (weight μAc/4). Bandwidth is 2fm.

Find the time domain and frequency domain expressions for single tone DSB-FC AM modulated wave. Also, show the spectrum of the modulated signal.

Time-domain expression

Let the message and carrier be

m(t)=Amcos⁡2πfmt,c(t)=Accos⁡2πfct,fc≫fmm(t) = A_m\cos2\pi f_mt, \qquad c(t) = A_c\cos2\pi f_ct, \quad f_c \gg f_m

In DSB-FC AM the carrier amplitude varies linearly with m(t)m(t):

s(t)=[Ac+Amcos⁡2πfmt]cos⁡2πfct=Ac[1+μcos⁡2πfmt]cos⁡2πfct,μ=AmAc\begin{aligned} s(t) &= [A_c + A_m\cos2\pi f_mt]\cos2\pi f_ct \\ &= A_c[1 + \mu\cos2\pi f_mt]\cos2\pi f_ct, \quad \mu = \frac{A_m}{A_c} \end{aligned}

Using cos⁡Acos⁡B=12[cos⁡(A−B)+cos⁡(A+B)]\cos A\cos B = \tfrac12[\cos(A-B) + \cos(A+B)]:

s(t)=Accos⁡2πfct+μAc2cos⁡2π(fc+fm)t+μAc2cos⁡2π(fc−fm)ts(t) = A_c\cos2\pi f_ct + \frac{\mu A_c}{2}\cos2\pi(f_c+f_m)t + \frac{\mu A_c}{2}\cos2\pi(f_c-f_m)t

Three components: carrier, upper side frequency (USF), lower side frequency (LSF).

 s(t):   envelope Ac(1 + u cos wm t)
       Ac(1+u) _      ____
              / \/\/\/    \/\
   ..........|..............|....  0
              \ /\/\/\    /\/
       -Ac(1+u) -      ----

Frequency-domain expression

Taking the Fourier transform, using cos⁡2πf0t↔12[δ(f−f0)+δ(f+f0)]\cos2\pi f_0t \leftrightarrow \tfrac12[\delta(f-f_0) + \delta(f+f_0)]:

S(f)=Ac2[δ(f−fc)+δ(f+fc)]+μAc4[δ(f−fc−fm)+δ(f+fc+fm)]+μAc4[δ(f−fc+fm)+δ(f+fc−fm)]\begin{aligned} S(f) = {} & \frac{A_c}{2}[\delta(f-f_c) + \delta(f+f_c)] \\ & + \frac{\mu A_c}{4}[\delta(f-f_c-f_m) + \delta(f+f_c+f_m)] \\ & + \frac{\mu A_c}{4}[\delta(f-f_c+f_m) + \delta(f+f_c-f_m)] \end{aligned}

Spectrum

                 S(f)
         Ac/2              Ac/2
          |                 |
   uAc/4  |  uAc/4   uAc/4  |  uAc/4
     |    |    |       |    |    |
 ----+----+----+---0---+----+----+---> f
 -fc-fm -fc -fc+fm   fc-fm  fc  fc+fm
  • Carrier impulses of weight Ac/2A_c/2 at ±fc\pm f_c.
  • Side-frequency impulses of weight μAc/4\mu A_c/4 at ±(fc±fm)\pm(f_c \pm f_m).
  • Bandwidth: B=(fc+fm)−(fc−fm)=2fmB = (f_c + f_m) - (f_c - f_m) = 2f_m.

Power (load RR): Pt=Ac22R(1+μ22)P_t = \dfrac{A_c^2}{2R}\left(1 + \dfrac{\mu^2}{2}\right), efficiency η=μ22+μ2\eta = \dfrac{\mu^2}{2 + \mu^2} (max 33.3% at μ=1\mu = 1).

✓ Answer checked by Claude Opus 5.5 (high effort)

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