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Demodulation of DSB-FC AM

Short answer

Envelope detector: diode conducts on positive half-cycles, charging a capacitor to peak; capacitor discharges through resistor between peaks, following the AM envelope. A DC-blocking capacitor removes carrier bias to yield m(t). The RC time constant must be large relative to carrier period and small relative to message period.

Describe any one method of demodulating DSB-FC AM signal.

DSB-FC (conventional AM) can be demodulated by the square law detector or the envelope detector. The envelope detector is the most widely used method and is described here.

Envelope detector

An envelope detector is a diode–RC circuit whose output follows the envelope Ac[1+kam(t)]A_c[1 + k_am(t)] of the AM wave.

            D
 AM in o---|>|----+--------+-------||----o  m(t)
   s(t)           |        |      Cc
                  C        R     (DC block)
                  |        |
       o----------+--------+-------------o

Input: s(t)=Ac[1+kam(t)]cos⁡ωcts(t) = A_c[1 + k_am(t)]\cos\omega_ct, with ∣kam(t)∣≤1|k_am(t)| \le 1.

Working

  1. Charging: During each positive half cycle, when the input exceeds the capacitor voltage, the diode conducts and CC charges rapidly to the peak value. The charging time constant rfCr_fC (rfr_f = diode + source resistance) is very small compared to the carrier period.
  2. Discharging: When the input falls below the capacitor voltage, the diode is reverse biased; CC discharges slowly through RR until the next positive peak.
  3. The capacitor voltage thus follows the positive peaks (envelope) with a small carrier-frequency ripple.
  4. A coupling capacitor CcC_c removes the DC term AcA_c, leaving Ackam(t)A_ck_am(t), i.e. the message.
 AM input            Detector output
  /\  /\/\/\  /\        ___
 /  \/      \/  \     _/   \_    _/   (follows envelope,
 \  /\      /\  /             \__/     small ripple)
  \/  \/\/\/  \/

Choice of time constant

1fc≪RC≪1W\frac{1}{f_c} \ll RC \ll \frac{1}{W}
  • RC≫1/fcRC \gg 1/f_c: the capacitor does not discharge much between carrier peaks (low ripple).
  • RC≪1/WRC \ll 1/W: the voltage can follow the fastest change of the envelope.

Distortions

  • Diagonal clipping: if RCRC is too large, the output cannot follow a fast-falling envelope. Avoid by
RC≤1−μ2μ ωmRC \le \frac{\sqrt{1 - \mu^2}}{\mu\,\omega_m}
  • Negative peak clipping: caused when the AC load (after CcC_c) is much smaller than the DC load RR; keep μ≤Rac/Rdc\mu \le R_{ac}/R_{dc}.
  • Over-modulation (μ>1\mu > 1): envelope no longer equals m(t)m(t), so the output is distorted.

Advantages and limitations

  • Very simple, cheap, no local oscillator or synchronisation needed: used in all broadcast AM receivers.
  • Works only for DSB-FC with μ≤1\mu \le 1; cannot demodulate DSB-SC or SSB; shows a threshold effect at low input SNR.

Example design: for fc=1f_c = 1 MHz and W=5W = 5 kHz, 1 μs≪RC≪200 μs1\ \mu s \ll RC \ll 200\ \mu s; choose RC≈20 μsRC \approx 20\ \mu s (e.g. R=10R = 10 kΩ, C=2C = 2 nF).

✓ Answer checked by Claude Opus 5.5 (high effort)

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