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Compare AM systems; one method of DSB-FC generation

Short answer

DSB-FC: bandwidth 2W, power P_c(1+μ²/2); DSB-SC: 2W, P_c μ²/2; SSB: W, P_c μ²/4; VSB: slightly >W. DSB-FC generation: sum of m(t) and carrier applied to square-law device (output a1·v1+a2·v1²), then bandpass filter at f_c extracts DSB-FC with μ=2a2/a1.

Compare various types of AM systems in terms of transmission power and transmission bandwidth. Explain any one method generating DSB-FC AM.

AM systems differ in which parts of the spectrum (carrier, USB, LSB) are sent. This changes the power that must be transmitted and the bandwidth occupied.

Comparison (single tone, modulation index μ\mu, message bandwidth WW)

TypeTransmitted powerBandwidthRemarks
DSB-FCPc(1+μ2/2)P_c(1+\mu^2/2)2W2WMax efficiency 33.3% at μ=1\mu=1
DSB-SCPc μ2/2P_c\,\mu^2/22W2WCarrier suppressed, 100% useful power
SSB-SCPc μ2/4P_c\,\mu^2/4WWHalf bandwidth, least power
VSBslightly more than SSBW+fvW + f_vfvf_v = vestige width

Here Pc=Ac2/2P_c = A_c^2/2 (normalized power). For μ=1\mu = 1, DSB-FC needs 1.5Pc1.5P_c, DSB-SC needs 0.5Pc0.5P_c (66.7% saving) and SSB needs 0.25Pc0.25P_c (83.3% saving).

Square-law modulator for DSB-FC

A square-law modulator uses a non-linear device (diode or transistor biased in its non-linear region) whose output is

v2(t)=a1v1(t)+a2v12(t)v_2(t) = a_1 v_1(t) + a_2 v_1^2(t)
 m(t) --->(+)--->[ Non-linear ]--->[ BPF at fc ]---> s(t)
           ^      [  device   ]     [ BW = 2W  ]
 Accos wct-|

The input is v1(t)=Accos⁡ωct+m(t)v_1(t) = A_c\cos\omega_c t + m(t). Then

v2(t)=a1Accos⁡ωct+a1m(t)+a2m2(t)+a2Ac2cos⁡2ωct+2a2Ac m(t)cos⁡ωct\begin{aligned} v_2(t) &= a_1 A_c\cos\omega_c t + a_1 m(t) + a_2 m^2(t) \\ &\quad + a_2A_c^2\cos^2\omega_c t + 2a_2 A_c\, m(t)\cos\omega_c t \end{aligned}

A band-pass filter centred at fcf_c with bandwidth 2W2W keeps only the terms near fcf_c:

s(t)=a1Ac[1+2a2a1m(t)]cos⁡ωcts(t) = a_1A_c\left[1 + \frac{2a_2}{a_1}m(t)\right]\cos\omega_c t

This is DSB-FC AM with amplitude sensitivity ka=2a2/a1k_a = 2a_2/a_1. The terms m(t)m(t), m2(t)m^2(t) (around 0 to 2W2W) and cos⁡2ωct\cos 2\omega_c t (around 2fc2f_c) are rejected. This needs fc>3Wf_c > 3W so the spectra do not overlap.

✓ Answer checked by Claude Opus 5.5 (high effort)

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