- 2068 Magh (old course) · 6 marks
Idealized stress-strain diagram of steel
Short answer
Mild steel is idealized as elastic-perfectly plastic with a yield plateau at f_y, elastic modulus E=2×10^5 N/mm², and yield strain 0.00125 for f_y=250. High tensile steel has no distinct yield point; its yield is the 0.2% proof stress, idealized as elastic up to that stress then flat, with lower ductility.
Show the idealized stress-strain diagram for mild steel and high tensile steel used in the design of steel structures.
The real stress-strain curve is idealised for design (IS 800:2007).
Mild steel (E250)
stress
fu | ___------.
| _-/ \
fy |-------+==============+ <- yield plateau
| /|
| / |
| / | E = 2x10^5
| / |
|__/____|______________|____ strain
0.00125 ~0.014 ~0.2
- Elastic line up to with slope N/mm²; yield strain for .
- Constant stress (yield plateau) up to roughly 10-15 times (strain hardening starts at about 0.014).
- Strain hardening up to the ultimate stress ( N/mm²) at a strain of about 0.15-0.2, then necking and fracture.
- For design the curve is idealised as elastic-perfectly plastic (bilinear): up to , then .
High tensile steel (E350-E450, cold-worked)
stress
fu | ___---
| _-/
0.2%|------_/
proof /
| /
| /
|___/____|__________ strain
0.002 offset
- No definite yield point or plateau; the stress rises smoothly.
- The yield stress is taken as the 0.2% proof stress (found by a line parallel to the elastic part, drawn from 0.002 strain).
- Idealised as elastic up to the proof stress and then flat (or rising slightly). Ductility is lower than that of mild steel.
✓ Answer checked by Claude Opus 5.5 (high effort)
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