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Idealized stress-strain, characteristic strength

Short answer

Concrete idealized curve: parabola to 0.002 strain then horizontal to 0.0035, design stress 0.446fck. Steel (HYSD) idealized curve: linear to 0.8fy then curve to fy with 0.002 plastic strain, design stress 0.87fy. Characteristic strength: fck = 5% fractile 28-day cube strength for concrete; fy = 5% fractile yield/proof stress for steel.

What do you understand by idealized stress-strain diagram of concrete and steel bar? Draw idealized stress-strain diagrams. Define characteristic strength of concrete and steel.

Idealised stress-strain diagram

The actual stress-strain curves of concrete and steel are irregular. For design, they are replaced by simplified (idealised) curves given in IS 456:2000.

Concrete (Fig. 21): a parabola from zero to a strain of 0.002, then a horizontal line up to 0.0035; the peak design stress is 0.67fck/1.5=0.446fck0.67f_{ck}/1.5=0.446f_{ck}.

Steel:

  • HYSD bars (Fig. 23B): linear up to 0.8fy0.8f_y (slope Es=2×105E_s=2\times10^5 N/mm2^2), then a curve up to fyf_y with a plastic strain of 0.002; the design curve is scaled by 1/1.151/1.15 to peak at 0.87fy0.87f_y.
  • Mild steel (Fig. 23A): linear up to fyf_y, then horizontal (elastic-perfectly plastic); the design curve is capped at 0.87fy0.87f_y.
 Concrete (IS 456 Fig. 21)        Steel (Fe415, Fig. 23B)
 stress                           stress
 0.67fck |   _______________      fy   |     ______  actual
         |  /               |     0.87fy|  __/ ______ design
 (design |/                 |           |_/ /
 0.446fck)                  |           |/ /
         +------------------>          +----------------> strain
        0.002          0.0035            Es=2x10^5   0.87fy/Es+0.002

Characteristic strength

  • Concrete: the compressive strength fckf_{ck} of 150 mm cubes at 28 days, below which not more than 5% of test results are expected to fall. M20 means fck=20f_{ck}=20 N/mm2^2.
  • Steel: the yield stress (or 0.2% proof stress) fyf_y, below which not more than 5% of test results are expected to fall. Fe415 means fy=415f_y=415 N/mm2^2.

Both are obtained from fk=fm−1.65sf_k=f_m-1.65s, where fmf_m is the mean strength and ss the standard deviation.

✓ Answer checked by Claude Opus 5.5 (high effort)

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