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Circular Sal column, open shed, 200 kN

Short answer

Provide a circular Sal column of diameter 180 mm. Equivalent square side = 159.5 mm, S/a = 21.94 (long), fc = 8.66 N/mm², capacity = 220 kN > 200 kN.

Design a circular salwood column to be used in an open shed, to carry an axial load of 200 kN. The column is 3.5 m high.

Approach. IS 883:1994 cl. 7.6.1.6: the permissible load on a circular column must not exceed that of a square column of equal cross-sectional area. So the circular column is designed through its equivalent square side aa, with a2=πD2/4a^2 = \pi D^2/4, i.e. a=0.886Da = 0.886D.

Data and permissible stresses

Height (unsupported length) S=3.5S = 3.5 m, axial load N=200N = 200 kN, pin ends.

Species: Sal (Shorea robusta), Group A. Location: outside. Grade: Grade I (standard) (Table 1 values are for Grade I).

Permissible stresses (IS 883:1994 Table 1, outside location):

PropertyTable 1 value (N/mm²)Used (N/mm²)
Bending / tension along grain fbf_b14.014.00
Compression parallel to grain fcpf_{cp}9.49.40
Compression perpendicular to grain fcnf_{cn}3.53.50
Horizontal shear HH0.940.94
Modulus of elasticity EE1267012670

An open shed is an outside location; the grade is not stated, so Grade I is used.

Trial section

Try diameter D=180D = 180 mm. Area A=πD2/4=25,447A = \pi D^2/4 = 25,447 mm². Equivalent square side:

a=0.886D=159.5 mma = 0.886D = 159.5\ \text{mm}

Slenderness and permissible stress

S/a=3500159.5=21.94K8=0.584Efcp=0.584126709.40=21.44\begin{aligned} S/a &= \frac{3500}{159.5} = 21.94 \\ K_8 &= 0.584\sqrt{\frac{E}{f_{cp}}} = 0.584\sqrt{\frac{12670}{9.40}} = 21.44 \end{aligned}

S/a=21.94>K8=21.44S/a = 21.94 > K_8 = 21.44, so it is a long column (S/a<50S/a < 50, OK):

fc=0.329E(S/a)2=0.329×1267021.942=8.66 N/mm2f_c = \frac{0.329E}{(S/a)^2} = \frac{0.329\times12670}{21.94^2} = 8.66\ \text{N/mm}^2

Check

P=fcA=8.66×25,447/103=220 kN>200 kNP = f_cA = 8.66\times25,447/10^3 = 220\ \text{kN} > 200\ \text{kN}

Safe.

Answer: provide a circular Sal column of diameter 180 mm. (Its permissible load equals that of a 160 mm square column of the same area.)

✓ Answer checked by Claude Opus 5.5 (high effort)

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