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Wind pressure on roof in Birgunj

Short answer

Using the given combined factor, Vz = 60 x 0.70 = 42 m/s and pz = 0.6Vz^2 = 1.06 kN/m^2. For alpha = 28 degrees, h/w = 0.75 and Cpi = +/-0.2, the worst net pressure is 1.06 kN/m^2 suction on slope EG (wind 90 degrees).

A building is situated in Birgunj, where the basic wind speed is found to be 60 m/sec. Find the wind pressure for the design of sloping roof of the building having following data: Angle of slope of roof, α\alpha = 28° Building height ratio, h/w = 0.75 K1×K2×K3K_1 \times K_2 \times K_3 = 0.70

Data. Vb=60V_b = 60 m/s (given), k1k2k3=0.70k_1k_2k_3 = 0.70 (combined, given), α=28∘\alpha = 28^\circ, h/w=0.75h/w = 0.75 (so the row 1/2<h/w≤3/21/2 < h/w \le 3/2 of Table 5). Permeability is not stated; normal permeability is assumed (Cpi=±0.2C_{pi} = \pm0.2).

Step 1: Design wind speed and pressure

Vz=Vb (k1k2k3)=60×0.70=42.0 m/spz=0.6Vz2=0.6×42.02=1058 N/m2=1.058 kN/m2\begin{aligned} V_z &= V_b\,(k_1k_2k_3) = 60\times0.70 = 42.0\ \text{m/s} \\ p_z &= 0.6V_z^2 = 0.6\times42.0^2 = 1058\ \text{N/m}^2 = 1.058\ \text{kN/m}^2 \end{aligned}

Step 2: External pressure coefficients (Table 5, interpolated between α=20∘\alpha = 20^\circ and 30∘30^\circ)

For α=28∘\alpha = 28^\circ and h/w=0.75h/w = 0.75: windward Cpe=−0.7+0.8×0.5=−0.30C_{pe} = -0.7 + 0.8\times0.5 = -0.30; leeward Cpe=−0.5C_{pe} = -0.5; for wind at 90°: EG =−0.80= -0.80, FH =−0.76= -0.76 (interpolated).

Step 3: Net design pressure pd=(Cpe−Cpi)pzp_d = (C_{pe} - C_{pi})p_z

SurfaceCpeC_{pe}pdp_d (N/m²), Cpi=+0.2C_{pi} = +0.2pdp_d (N/m²), Cpi=−0.2C_{pi} = -0.2
Windward slope EF (wind 0°)-0.30-529-106
Leeward slope GH (wind 0°)-0.50-741-318
Slope EG (wind 90°)-0.80-1058-635
Slope FH (wind 90°)-0.76-1016-593

(Negative = suction, acting away from the roof.)

Answer

Design wind speed Vz=42V_z = 42 m/s; design wind pressure pz=1058p_z = 1058 N/m² (≈1.06\approx 1.06 kN/m²). The most severe net pressure on the roof is 1058 N/m² (1.06 kN/m²) suction on Slope EG (wind 90°) (net Cp=−1.00C_p = -1.00). On the windward slope for wind normal to the ridge it is −529-529 N/m² with Cpi=+0.2C_{pi} = +0.2 and −106-106 N/m² with Cpi=−0.2C_{pi} = -0.2.

✓ Answer checked by Claude Opus 5.5 (high effort)

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