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Wind pressure on sloping roof, Madras

Short answer

Using IS 875, Madras Vb = 50 m/s; with Category 2, Class A and height below 10 m, Vz = 50 m/s and pz = 0.6Vz^2 = 1.50 kN/m^2. For alpha = 26.6 degrees, h/w = 0.6 and Cpi = +/-0.2, the worst net coefficient is -1.00, giving 1.50 kN/m^2 suction.

Find the design wind pressure on a sloping roof of span 10 m and pitch ¼. The height of the eves is 6 m above ground. The building is situated in Madras and its permeability is normal.

Data and assumptions. Span 10 m, pitch 1/41/4: rise 2.5 m, α=26.57∘\alpha = 26.57^\circ. Eaves height h=6h = 6 m, w=10w = 10 m, h/w=0.6h/w = 0.6. Madras: Vb=50V_b = 50 m/s (IS 875 Part 3, Appendix A). Terrain Category 2, Class A (building below 20 m); mean roof height =7.25= 7.25 m, below 10 m. k1=1k_1 = 1, k3=1k_3 = 1 (not given). Normal permeability: Cpi=±0.2C_{pi} = \pm0.2.

Step 1: Design wind speed (IS 875 Part 3:1987, cl. 5.3)

Vz=Vb k1k2k3V_z = V_b\,k_1k_2k_3
  • Basic wind speed Vb=50V_b = 50 m/s.
  • Risk coefficient k1=1.00k_1 = 1.00 (50-year life; Table 1).
  • Terrain, height and size factor k2k_2: Category 2, Class A, at height 7.25 m: k2=1.00k_2 = 1.00 (constant up to 10 m) (Table 2).
  • Topography factor k3=1.000k_3 = 1.000 (flat site).
Vz=50×1.00×1.000×1.000=50.00 m/spz=0.6Vz2=0.6×50.002=1500 N/m2=1.500 kN/m2\begin{aligned} V_z &= 50\times1.00\times1.000\times1.000 = 50.00\ \text{m/s} \\ p_z &= 0.6V_z^2 = 0.6\times50.00^2 = 1500\ \text{N/m}^2 = 1.500\ \text{kN/m}^2 \end{aligned}

Step 2: Pressure coefficients (Table 5, pitched roof of rectangular clad building)

Height ratio h/w=0.60h/w = 0.60, roof angle α=26.6∘\alpha = 26.6^\circ. Values are interpolated between α=20∘\alpha = 20^\circ and 30∘30^\circ.

Internal pressure coefficient Cpi=±0.2C_{pi} = \pm0.2 (normal permeability), cl. 6.2.3.

SurfaceCpeC_{pe}Cpe−CpiC_{pe} - C_{pi} (Cpi=+0.2C_{pi}=+0.2)Cpe−CpiC_{pe} - C_{pi} (Cpi=−0.2C_{pi}=-0.2)pdp_d (N/m²), Cpi=+C_{pi}=+pdp_d (N/m²), Cpi=−C_{pi}=-
Windward slope EF (wind 0°)-0.37-0.57-0.17-858-258
Leeward slope GH (wind 0°)-0.50-0.70-0.30-1050-450
Slope EG (wind 90°)-0.80-1.00-0.60-1500-900
Slope FH (wind 90°)-0.73-0.93-0.53-1397-797

Design pressure normal to the roof: pd=(Cpe−Cpi) pzp_d = (C_{pe} - C_{pi})\,p_z (positive = towards the surface, negative = suction). The most severe case is Slope EG (wind 90°), with Cpe−Cpi=−1.00C_{pe} - C_{pi} = -1.00, so pd=−1500p_d = -1500 N/m² =−1.500= -1.500 kN/m².

Answer

  • Design wind speed Vz=50.0V_z = 50.0 m/s; design wind pressure pz=1500p_z = 1500 N/m² (1.50 kN/m²).
  • Net design pressure on the roof: up to 15001500 N/m² (1.50 kN/m²), suction.

✓ Answer checked by Claude Opus 5.5 (high effort)

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