- Practice · 4+4 marks
Radiation hazards, protection and shielding
Short answer
Nuclear radiation can cause acute effects like radiation sickness and death at high doses, and delayed effects like cancer and genetic mutations. Protection principles: minimize time, maximize distance (inverse-square law), and use shielding. Half-value layer for 1 MeV gamma in lead is 0.86 cm; thickness for 1% transmission is 5.7 cm; dose rate at 4 m is 0.25 mSv/h.
(a) Explain the health hazards of nuclear radiation and the three principles of radiation protection. (b) Gamma rays of 1 MeV pass through lead for which the linear attenuation coefficient is 0.806 cm⁻¹. Find the half-value layer and the thickness of lead needed to reduce the intensity to 1 % of its original value. If the dose rate is 4 mSv/h at 1 m from a small source, what is it at 4 m, neglecting absorption?
(a) Health hazards
Ionising radiation (alpha, beta, gamma, X-rays, neutrons) breaks chemical bonds and damages cells.
- Acute (deterministic) effects from a high dose in a short time: radiation sickness (nausea, hair loss, burns), and death above about 4–5 Sv whole-body.
- Stochastic (delayed) effects: cancer (leukaemia, thyroid, lung) and shortening of life, which appear after years; their probability rises with dose.
- Genetic effects: mutations in reproductive cells that are passed on to children.
- Internal exposure by inhaling or swallowing radioactive material (e.g. iodine-131 in the thyroid, radon, strontium-90 in bones) is especially dangerous for alpha emitters.
Units: activity in becquerel (Bq); absorbed dose in gray (Gy); equivalent dose in sievert (Sv). The public limit is about 1 mSv per year and the limit for radiation workers is about 20 mSv per year (averaged, ICRP).
Principles of protection
- Time: reduce the time of exposure; dose is proportional to time.
- Distance: dose falls with the square of the distance from a point source, .
- Shielding: place absorbers between the source and the person: lead and concrete for gamma and X-rays, plastic or perspex for beta, water or polythene (hydrogen-rich) and boron/cadmium for neutrons, and paper or skin for alpha.
Other measures are containment, ventilation, personal monitoring badges (TLD) and the ALARA principle (as low as reasonably achievable).
(b) Shielding calculation
Attenuation law: .
Half-value layer:
For 1 % transmission, :
Distance effect:
Answer: HVL = 0.86 cm; thickness for 1 % = 5.7 cm of lead; dose rate at 4 m = 0.25 mSv/h.
✓ Answer checked by Claude Opus 5.5 (high effort)
Related questions
- Energy from D-T fusion and U-235 fission · Energy Resources, chapter 7
- Flat plate collector useful heat and outlet temperature · Energy Resources, chapter 2
- Derivation of Betz limit for wind turbine · Energy Resources, chapter 4
- Nuclear hazards and effects · Energy Environment and Society, chapter 4
- Clay 10 m, 2.54 cm sample, half settlement · Soil Mechanics, chapter 9
- RF/MW radiation hazards and safety practices · RF and Microwave Engineering, chapter 7 · asked 4×
- Short note: Microwave radiation hazards · RF and Microwave Engineering, chapter 7 · asked 3×