- 2068 Jestha · 10 marks
Best of P and Q for 5-year study period
Short answer
Calculate present worth over the 5-year study: PW(P) = Rs. 289,203, PW(Q) = Rs. 335,120. Incremental IRR of P over Q is about -2.1% below 10% MARR. Project Q is best.
Select the best project. Required study period is 5 years.
| Project P | Project Q | |
|---|---|---|
| Initial Investment (Rs.) | 5,00,000 | 3,50,000 |
| Annual net revenue (Rs.) | 2,00,000 | 1,75,000 |
| Salvage value (Rs.) | 50,000 | 35,000 |
| Useful life (Years) | 6 | 5 |
| MARR | 10% | 10% |
Study period = 5 years, MARR = 10%.
Assumptions
- Project Q has a life equal to the study period (5 years): salvage Rs. 35,000 is received at year 5.
- Project P has a life of 6 years but is needed for 5 years only. It is sold at the end of year 5; as no other market value is given, take the stated salvage (Rs. 50,000) as the year-5 market value.
Cash-flow diagram (Rs., '000)
P: 200 200 200 200 200+50
| | | | |
0 --1-----2-----3-----4------5--> year
v 500
Q: 175 175 175 175 175+35
| | | | |
0 --1-----2-----3-----4------5--> year
v 350
Present worth
(P/A, 10%, 5) = 3.7908, (P/F, 10%, 5) = 0.6209
PW(P) = -500,000 + 200,000(3.7908) + 50,000(0.6209) = -500,000 + 758,157 + 31,046 = Rs. 289,203
PW(Q) = -350,000 + 175,000(3.7908) + 35,000(0.6209) = -350,000 + 663,388 + 21,732 = Rs. 335,120
Check by incremental IRR (P over Q)
Extra investment 150,000, extra net revenue 25,000 per year, extra salvage 15,000 at year 5. PW of increment at 10% = -150,000 + 25,000(3.7908) + 15,000(0.6209) = -45,917 < 0 Incremental IRR ≈ -2.1% < 10%, so the extra investment in P is not justified.
| Project | IRR | PW at 10% |
|---|---|---|
| P | 30.1% | 289,203 |
| Q | 42.1% | 335,120 |
Answer: Select Project Q (higher PW, Rs. 335,120, and the extra investment in P earns less than MARR).
✓ Answer checked by Claude Opus 5.5 (high effort)
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