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Modified BCR with co-termination, AW

Short answer

Co-terminated at 5 years, salvage 10% first cost, MARR 15%. Modified B/C: A=1.323, B=1.083. Incremental B/C (B over A) = 0.764 < 1. Select Project A.

Co-terminating both projects at 5 years and select the best project by modified BCR (using AW formulation). Take MARR = 15%. Salvage value of each project = 10% of first cost.

PROJECTFirst CostAnnual BenefitsAnnual O & M CostsUseful Life
ARs. 4,00,000Rs. 175,000Rs. 25,0006 years
BRs. 7,00,000Rs. 250,000Rs. 35,0008 years

Co-termination: both projects are used for the same study period of 5 years (the shorter of the two lives is 6, and the study period is stated as 5). The projects are truncated at year 5 and the asset is assumed sold then for its salvage value, taken as 10% of first cost (assumption: this is the market value at year 5 for both).

Modified B/C (AW formulation) = (AW of benefits - AW of O&M) / CR, where CR = I(A/P, 15%, 5) - S(A/F, 15%, 5) is the capital recovery cost. (A/P, 15%, 5) = 0.2983, (A/F, 15%, 5) = 0.1483

Project A (I = 400,000, S = 40,000)

CR = 400,000(0.2983) - 40,000(0.1483) = 119,326 - 5,933 = 113,394 Modified B/C = (175,000 - 25,000) / 113,394 = 1.323

Project B (I = 700,000, S = 70,000)

CR = 700,000(0.2983) - 70,000(0.1483) = 208,821 - 10,382 = 198,439 Modified B/C = (250,000 - 35,000) / 198,439 = 1.083

Incremental analysis (B over A)

Extra net benefit = 215,000 - 150,000 = 65,000 per year Extra CR = 198,439 - 113,394 = 85,045 Incremental B/C = 65,000 / 85,045 = 0.764 < 1

Both are above 1, so each is acceptable alone, but the extra investment in B does not pay for itself.

ProjectCR (Rs./yr)Modified B/CAW (net)
A113,3941.32336,606
B198,4391.08316,561

Answer: Select Project A (higher modified B/C and incremental B/C of B over A is only 0.76).

✓ Answer checked by Claude Opus 5.5 (high effort)

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