- 2079 Chaitra · 6 marks
Manometer between oil and water pipes
Short answer
At D–D: left, p_A + 0.875×9.81×1.5 = p_A + 12.876 kN/m²; right, p_B + 1.25×9.81×2.25 = p_B + 27.591 kN/m². Equate: p_A − p_B = 14.715 kN/m², pipe A pressure higher.
Two pipes as shown in figure convey oil of specific gravity of 0.875 and water respectively. Both the liquids in the pipes are under pressure. The pipes are connected to a U-tube manometer and the hoses connecting the pipes to the tubes are filled with the corresponding liquids. Find the difference of pressure in two pipes if the level of manometric liquid having a specific gravity of 1.25 is 2.25 m higher in the right limb than the lower level of oil in the left limb of the manometer. [Figure: pipe A (oil) and pipe B (water) connected through an inverted U-tube manometer; the centre of A is 1.5 m above the lower oil level D–D, and the manometric liquid in the right limb stands 2.25 m above D–D (level E–F).]
Equate the pressures on the horizontal plane D–D (the lower oil level / top of the manometric liquid in the left limb), since below it the same manometric liquid is continuous.
Given: oil , manometric liquid , water . Centre of A is 1.5 m above D–D. Manometric liquid in the right limb stands 2.25 m above D–D (level E–F). The centre of B is taken at level E–F, as no other height is given.
A (oil) o o B (water) -- E-F
| |
| 1.5 m oil | 2.25 m of
| | liquid S=1.25
D ------+---- S = 1.25 ------+------ D
Pressure at D–D, left limb
Pressure at D–D, right limb
Equate
Answer: kN/m² (≈ 14.72 kPa); pipe A (oil) is at the higher pressure.
✓ Answer checked by Claude Opus 5.5 (high effort)
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