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Pipe flow regimes and velocity profiles

Short answer

Flow is classified by Reynolds number: Re<2000 laminar, 2000≤Re≤4000 transitional, Re>4000 turbulent. Laminar profile is parabolic with u_max=2V; turbulent profile is flatter with a thin viscous sublayer, u_max≈1.2V, and velocity changes steeply near the wall.

How do you numerically classify laminar, transitional and turbulent flow in pipes? Differentiate laminar and turbulent velocity profiles in pipe flow with neat sketch and labels.

Numerical classification (Reynolds number)

Flow in pipes is classified by the Reynolds number, the ratio of inertia force to viscous force:

Re=ρVDμ=VDνRe = \frac{\rho V D}{\mu} = \frac{VD}{\nu}
Flow typeReynolds number (pipe)
LaminarRe<2000Re < 2000
Transitional2000≤Re≤40002000 \le Re \le 4000
TurbulentRe>4000Re > 4000

Example: water (ν=10−6\nu = 10^{-6} m²/s) at 1 m/s in a 0.1 m pipe: Re=105Re = 10^5, so turbulent.

Velocity profiles

 Laminar (parabolic)       Turbulent (flatter)
 |=====================    |=====================
 |-->                      |------->
 |------>                  |--------->
 |--------->  u_max = 2V   |---------->  u_max ~ 1.2V
 |------>                  |--------->
 |-->                      |------->
 |=====================    |=====================
   wall   u = 0               thin laminar sublayer
  • Laminar: velocity varies parabolically with radius (Hagen–Poiseuille):
u=umax(1−r2R2),umax=2Vˉu = u_{max}\left(1 - \frac{r^2}{R^2}\right), \quad u_{max} = 2\bar V
  • Turbulent: mixing evens out the velocity, so the profile is flat in the core and changes steeply near the wall; approximately the power law u=umax(y/R)1/7u = u_{max}(y/R)^{1/7}, with umax≈1.2Vˉu_{max} \approx 1.2\bar V and a thin laminar sub-layer at the wall.
FeatureLaminar profileTurbulent profile
ShapeParabolicFlat core, steep at wall
umax/Vˉu_{max}/\bar V2.0about 1.2
Wall shearLowHigh
Velocity lawu=umax(1−r2/R2)u = u_{max}(1 - r^2/R^2)Log law or (y/R)1/7(y/R)^{1/7}
KE factor α\alpha2.01.03–1.10
Head losshf∝Vh_f \propto V, f=64/Ref = 64/Rehf∝V1.75h_f \propto V^{1.75} to V2V^2

✓ Answer checked by Claude Opus 5.5 (high effort)

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