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Lewis equation for beam strength of a gear tooth

Short answer

Lewis treated the tooth as a cantilever beam with full tangential load at the tip, neglecting radial force and stress concentration. The permissible load is Wt = σb b π m y, where y, the form factor, is 0.154 – 0.912/z for 20° full-depth teeth.

Derive the Lewis equation for the beam strength of a spur gear tooth, stating the assumptions. Define the Lewis form factor and state its expression for 20 degree full-depth teeth.

Lewis (1892) treated a gear tooth as a cantilever beam loaded at its tip by the full tangential load, and found its load-carrying strength in bending.

Assumptions

  • The full load WtW_t acts at the tip of one tooth only.
  • The load is uniformly distributed across the face width bb.
  • The radial component (compression) and friction are neglected.
  • The effect of stress concentration at the root is neglected.
  • The tooth is treated as a parabola (a beam of uniform strength), and the section of maximum stress is where the parabola touches the tooth profile.
         Wt
          |
          v
        __|__        <- tip
       /  |  \
      /   | h \  parabola
     /   _|_   \
    |<--- t --->|   critical section

Derivation

Let tt = tooth thickness at the critical section, hh = height of the load above that section, bb = face width.

Bending moment M=Wt hM = W_t\,h. Section modulus Z=bt26Z = \dfrac{b t^2}{6}.

σb=MZ=6 Wt hb t2\sigma_b = \frac{M}{Z} = \frac{6\,W_t\,h}{b\,t^2}

So the permissible tangential load is

Wt=σb b t26hW_t = \frac{\sigma_b\, b\, t^2}{6h}

The critical section is where the inscribed parabola touches the tooth profile. From the similar triangles of the parabola, t2=4hxt^2 = 4hx, where xx is a length fixed by the tooth profile. Substituting,

Wt=σb b⋅4hx6h=σb b 2x3W_t = \frac{\sigma_b\, b \cdot 4hx}{6h} = \sigma_b\, b\,\frac{2x}{3}

Multiplying and dividing by the circular pitch pc=πmp_c = \pi m:

Wt=σb b πm(2x3pc)W_t = \sigma_b\, b\, \pi m\left(\frac{2x}{3 p_c}\right)

The dimensionless term in brackets is the Lewis form factor yy:

Wt=σb b π m y\boxed{W_t = \sigma_b\, b\, \pi\, m\, y}

where σb\sigma_b is the allowable bending stress (σo\sigma_o for static conditions, or σoCv\sigma_o C_v with the velocity factor). Writing Y=πyY = \pi y gives the other form, Wt=σbbmYW_t = \sigma_b b m Y.

Form factor

yy depends on the tooth profile and the number of teeth zz; it increases with zz:

  • 20 degree full depth: y=0.154−0.912zy = 0.154 - \dfrac{0.912}{z}
  • 14.5 degree composite or full depth: y=0.124−0.684zy = 0.124 - \dfrac{0.684}{z}

For a given pair of gears, the design is based on the weaker of the pinion and the gear (the one with the smaller σby\sigma_b y). The pinion has fewer teeth, and so a smaller yy, but it is often made of a stronger material.

✓ Answer checked by Claude Opus 5.5 (high effort)

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