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Degree of freedom and Gruebler's criterion

Short answer

Degree of freedom is the number of independent inputs needed to fix all link positions. Gruebler's criterion for planar mechanisms: F = 3(n-1) - 2j1 - j2. For (i) n=7, j1=8, j2=1: F = 3(6) - 16 - 1 = 1. For (ii) n=6, j1=7, j2=0: F = 3(5) - 14 = 1. Both have one DOF.

Define degree of freedom of a mechanism. State Gruebler's criterion for planar mechanisms. Find the mobility of (i) a planar mechanism having 7 links (including the frame), 8 turning pairs and 1 cam-follower higher pair, and (ii) a six-link planar chain having 7 turning pairs.

Degree of freedom

The degree of freedom (DOF) or mobility of a mechanism is the number of independent input parameters (coordinates) that must be given to fix the position of every link with respect to the frame. A mechanism with F=1F = 1 needs one input (for example one motor) to give a definite motion.

Gruebler's criterion

For a planar mechanism, a free link has 3 DOF. Fixing one link as the frame removes 3 DOF. Each lower pair (turning or sliding, 1 DOF) removes 2 DOF and each higher pair removes 1 DOF. So

F=3(n−1)−2j1−j2F = 3(n-1) - 2j_1 - j_2

where nn = total number of links (including the frame), j1j_1 = number of lower pairs (single-DOF), j2j_2 = number of higher pairs (two-DOF).

  • F=1F = 1: constrained mechanism (definite motion).
  • F≤0F \le 0: structure (no motion).
  • F≥2F \ge 2: needs FF inputs, otherwise motion is indefinite.

Numerical (i)

Given n=7n = 7, j1=8j_1 = 8, j2=1j_2 = 1.

F=3(7−1)−2(8)−1=18−16−1=1F = 3(7-1) - 2(8) - 1 = 18 - 16 - 1 = 1

Numerical (ii)

Given n=6n = 6, j1=7j_1 = 7, j2=0j_2 = 0.

F=3(6−1)−2(7)=15−14=1F = 3(6-1) - 2(7) = 15 - 14 = 1

This is the Watt or Stephenson six-bar chain, which has one DOF.

Answer: (i) F=1F = 1, (ii) F=1F = 1; both mechanisms have definite motion with one input.

✓ Answer checked by Claude Opus 5.5 (high effort)

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