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Straight bevel gear geometry and formative teeth

Short answer

Pitch cone angle is angle between axis and pitch cone; cone distance is apex to large-end pitch radius; back cone is perpendicular to pitch cone at large end; formative teeth z'=z/cosγ (Tredgold). For z1=20, z2=40, m=6 mm, 90° shafts: γ1=26.57°, γ2=63.43°, d1=120 mm, d2=240 mm, A0=134.16 mm, maximum face width b_max=44.72 mm, z1'=22.36, z2'=89.44.

Define pitch cone angle, cone distance, back cone and formative (virtual) number of teeth for straight bevel gears. Explain Tredgold's approximation. A pair of straight bevel gears with 20 and 40 teeth, module 6 mm at the large end, connects shafts at 90 degrees. Find the pitch cone angles, pitch diameters, cone distance, the maximum recommended face width and the formative numbers of teeth.

Definitions

  • Pitch cone angle (γ\gamma): the angle between the gear axis and the pitch cone element.
  • Cone distance (A0A_0): the length of a pitch cone element from the apex to the large-end pitch circle.
  • Back cone: a cone whose elements are perpendicular to the pitch cone elements at the large end of the tooth. When developed (laid flat), it gives a spur gear.
  • Formative (virtual) number of teeth: the number of teeth on the spur gear whose pitch radius equals the back cone distance.

Tredgold's approximation

The tooth profile of a bevel gear is taken as that of a spur gear lying on the back cone surface. The back cone radius is rv=d2cos⁡γr_v = \dfrac{d}{2\cos\gamma}, so the virtual spur gear has pitch diameter d/cos⁡γd/\cos\gamma and

z′=zcos⁡γz' = \frac{z}{\cos\gamma}

This z′z' is used for tooth strength design and to check interference (z′z' need not be an integer).

       apex
        /|\
       / | \   A0 = cone distance
      /  |  \
     /   |   \
    /_(gamma)_\
    gear pitch dia d

Shafts at 90 degrees

For shaft angle Σ=90∘\Sigma = 90^\circ:

tan⁡γ1=z1z2,γ2=90∘−γ1\tan\gamma_1 = \frac{z_1}{z_2}, \qquad \gamma_2 = 90^\circ - \gamma_1

Calculation

γ1=tan⁡−12040=26.57∘,γ2=90∘−26.57∘=63.43∘\gamma_1 = \tan^{-1}\frac{20}{40} = 26.57^\circ, \qquad \gamma_2 = 90^\circ - 26.57^\circ = 63.43^\circ

Pitch diameters (large end):

d1=mz1=6×20=120 mm,d2=mz2=6×40=240 mmd_1 = mz_1 = 6 \times 20 = 120\ \text{mm}, \qquad d_2 = mz_2 = 6 \times 40 = 240\ \text{mm}

Cone distance:

A0=(d12)2+(d22)2=602+1202=134.16 mmA_0 = \sqrt{\left(\frac{d_1}{2}\right)^2 + \left(\frac{d_2}{2}\right)^2} = \sqrt{60^2 + 120^2} = 134.16\ \text{mm}

Face width limit (to avoid weak tooth tips and cutting problems): b≤A0/3b \le A_0/3 or 10m10m, whichever is less. Here 10m=6010m = 60 mm, so

bmax=134.163=44.72 mmb_{max} = \frac{134.16}{3} = 44.72\ \text{mm}

Formative numbers of teeth:

z1′=20cos⁡26.57∘=22.36,z2′=40cos⁡63.43∘=89.44z_1' = \frac{20}{\cos 26.57^\circ} = 22.36, \qquad z_2' = \frac{40}{\cos 63.43^\circ} = 89.44

Tooth proportions (large end): addendum =m=6= m = 6 mm, dedendum =1.2m=7.2= 1.2m = 7.2 mm.

Answer: γ1=26.57∘\gamma_1 = 26.57^\circ, γ2=63.43∘\gamma_2 = 63.43^\circ, d1=120d_1 = 120 mm, d2=240d_2 = 240 mm, A0=134.16A_0 = 134.16 mm, bmax=44.72b_{max} = 44.72 mm, z1′=22.36z_1' = 22.36, z2′=89.44z_2' = 89.44.

✓ Answer checked by Claude Opus 5.5 (high effort)

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