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Highway curves and effects without superelevation

Short answer

Without superelevation, the full centrifugal force must be resisted by friction, causing lateral skidding if v^2/(gR)>f, overturning if v^2/(gR)>b/(2h), load transfer, passenger discomfort, driver difficulty, and higher fuel and tyre wear, because no weight component opposes the outward force.

Explain the types of highway curves. What effects take place on a vehicle when it negotiates a horizontal curve without superelevation? Give reasons.

Types of highway curves

Horizontal curves

  • Simple circular curve - a single arc of constant radius joining two tangents.
  • Compound curve - two or more arcs of different radii in the same direction with a common tangent at the junction.
  • Reverse curve - two arcs bending in opposite directions.
  • Transition (spiral) curve - varying radius between a tangent and a circular curve.

Vertical curves

  • Summit (crest) curve - formed when an upgrade meets a downgrade or a lesser upgrade.
  • Valley (sag) curve - when a downgrade meets an upgrade or lesser downgrade.

Effects on a vehicle on a horizontal curve without superelevation

When the pavement is flat (no superelevation), the whole centrifugal force P=Wv2/(gR)P = Wv^2/(gR) must be resisted by lateral friction alone.

  1. Lateral skidding: if v2/(gR)>fv^2/(gR) > f the tyres slip sideways and the vehicle leaves the curve; a high speed or low ff (wet road) makes it likely.
  2. Overturning: if v2/(gR)>b/(2h)v^2/(gR) > b/(2h) the vehicle overturns about the outer wheels, a risk for high vehicles such as buses and trucks.
  3. Load transfer: the outer wheels carry more load than the inner wheels, so the outer tyres wear more and the load shifts.
  4. Passenger discomfort: passengers are thrown outward.
  5. Driver difficulty: to prevent skidding the driver must slow down, so the speed and capacity decrease; or, if he does not, he runs on the outer lane and may meet opposing vehicles.
  6. Higher fuel use and tyre wear.

Reason: the centrifugal force has no counterbalance except friction, and the friction available (f=0.15f = 0.15 at design) is usually not enough for the design speed. A superelevation ee (and an adequate radius) provides a component of weight against PP so that e+f=V2/(127R)e + f = V^2/(127R) is satisfied.

✓ Answer checked by Claude Opus 5.5 (high effort)

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