- 2076 Baisakh · 8 marks
Overtaking sight distance and zone, 60 kmph
Short answer
OSD ≈302 m. Minimum length of overtaking zone is 3 × OSD = 906 m.
The speed of overtaking vehicle is 60 kmph on a two way traffic road. If the acceleration of overtaking vehicle is 0.79 m/sec², a) Calculate safe overtaking sight distance b) Mention the minimum length of overtaking zone c) Draw a neat sketch of the overtaking zone and show the position of sign posts.
Data (IRC 66 / NRS 2070)
Speed of overtaking vehicle km/h, acceleration m/s², reaction time s. The speed of the overtaken vehicle is not given, so km/h (IRC), i.e. m/s. The opposing vehicle is taken at the design speed km/h.
(a) Safe overtaking sight distance
OSD = .
- Distance in reaction time: m
- Minimum spacing ( in m/s): m
- Overtaking time s
- Distance covered during overtaking: m
- Distance covered by the opposing vehicle: m
OSD is about 302 m.
(b) Minimum length of overtaking zone
IRC recommends a minimum length of 3 × OSD = 3 × 302 = 906 m (desirable 5 × OSD = 1510 m).
(c) Sketch of overtaking zone
Direction of travel ---->
[Sign: Overtaking zone] [Sign: End of overtaking zone]
|<----- Overtaking zone (min 3 x OSD) ----->|
=======|===========================================|=======
------- - - - - - - - - - - - - - - - - - - - - - - -------
=======|===========================================|=======
continuous broken centre line inside zone continuous
centre line centre line
(A "No overtaking" sign is placed beyond the end of the zone.
The opposite direction has its own zone and signs.)
Signs are placed at the start and end of the zone (for each direction of travel). The centre line is a broken line inside the zone and a continuous line outside it.
✓ Answer checked by Claude Opus 5.5 (high effort)
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