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Shear reinforcement and punching shear in footings

Short answer

Beam: at d from support compute τv=Vu/(bd)≤τc,max; if τv≤τc provide minimum stirrups; else Vus=Vu−τcbd, sv=0.87fyAsvd/Vus≤0.75d,300mm. Footing: check punching at d/2 from column face; force Vu=qu[BL−(a+d)(b+d)], perimeter b0=2(a+b+2d); τv=Vu/(b0d)≤ksτc, τc=0.25√fck, ks=0.5+βc≤1. Increase depth if not satisfied.

Write down the procedure for design of shear reinforcement. Also explain how the isolated footings are designed under punching shear.

Procedure for design of shear reinforcement (beam)

  1. Compute factored shear VuV_u at the critical section (distance dd from the support face).
  2. Nominal shear stress τv=Vubd\tau_v=\dfrac{V_u}{bd}; check τv≤τc,max\tau_v\le\tau_{c,max}.
  3. Find τc\tau_c from IS 456 Table 19 using pt=100Astbdp_t=\dfrac{100A_{st}}{bd} and fckf_{ck}.
  4. If τv≤τc\tau_v\le\tau_c, provide minimum stirrups: Asvb sv≥0.40.87fy\dfrac{A_{sv}}{b\,s_v}\ge\dfrac{0.4}{0.87f_y}.
  5. If τv>τc\tau_v>\tau_c, shear carried by steel Vus=Vu−τcbdV_{us}=V_u-\tau_cbd, then sv=0.87fyAsvdVus≤min⁡(0.75d, 300 mm)s_v=\frac{0.87f_yA_{sv}d}{V_{us}}\le\min(0.75d,\ 300\ \text{mm})
  6. Provide closer spacing near supports and wider spacing where shear is small.

Punching (two-way) shear in isolated footings

A column punches through the footing along a truncated pyramid. IS 456 (cl. 31.6) checks it at a section at d/2d/2 from the face of the column (critical perimeter b0b_0), in addition to one-way shear at dd from the face.

   plan                         section
  +--------------+              col
  |  +--------+  |           ____|__|____
  |  | col    |  |   d/2         \  /  45
  |  +--------+  |   |<--->|____/__\____
  |  critical    |    critical perimeter
  +--------------+

Steps

  1. Factored upward soil pressure qu=Pu/(footing area)q_u=P_u/(\text{footing area}) (net, excluding self weight).
  2. Punching shear force: Vu=qu[BL−(a+d)(b+d)]V_u=q_u\left[BL-(a+d)(b+d)\right] for a column a×ba\times b.
  3. Critical perimeter: b0=2[(a+d)+(b+d)]b_0=2[(a+d)+(b+d)].
  4. Nominal punching shear stress: τv=Vub0 d\tau_v=\dfrac{V_u}{b_0\,d}.
  5. Permissible punching shear stress: τc′=ksτc\tau_c'=k_s\tau_c, where ks=0.5+βc≤1k_s=0.5+\beta_c\le1 (βc\beta_c = short side/long side of column) and τc=0.25fck\tau_c=0.25\sqrt{f_{ck}}.
  6. Condition: τv≤τc′\tau_v\le\tau_c'. If not satisfied, increase the depth dd of the footing (shear reinforcement is not normally used in footings).
  7. Also check one-way (beam) shear at distance dd from the column face with τc\tau_c from Table 19 for the footing steel percentage.

✓ Answer checked by Claude Opus 5.5 (high effort)

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