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Design procedure of sloping glacis weir bay

Short answer

Design steps: collect hydraulic data, compute waterway via Lacey's perimeter and discharge intensity, set crest level from flood routing and canal FSL, find scour depth, determine downstream floor level and length using hydraulic jump conjugate depth, fix total floor length and cutoff depths via Bligh/Khosla, calculate floor thickness from uplift pressure, and provide protection aprons.

Write down the design procedure of sloping glacis weir bay in a typical diversion headworks (crest level, d/s floor level and length, total length of floor, cutoff depth and thickness of floor).

Design of the weir bay of a sloping-glacis weir (Garg / Punmia style).

Step 1: Data. Maximum flood QQ, HFL, pond level (PL), river bed levels, silt factor ff, afflux, safe exit gradient.

Step 2: Waterway and discharge intensity. Total waterway LL (from Lacey's perimeter, P=4.75QP = 4.75\sqrt Q), less the width of the undersluices and piers, gives the weir bay length. Discharge per metre q=Q/Lq = Q/L.

Step 3: Crest level. Fixed from the pond level and head required to pass the design flood over the crest: Q=23Cd2g L H3/2Q = \frac{2}{3}C_d\sqrt{2g}\,L\,H^{3/2} (crest level == HFL after afflux −- HH); also crest == canal FSL ++ regulator losses.

Step 4: Regime (scour) depth. R=1.35 (q2/f)1/3R = 1.35\,(q^2/f)^{1/3}.

Step 5: Downstream floor level and length.

  • Total energy EL=E_L = (u/s TEL) −- (d/s bed or floor level); HL=H_L = (u/s TEL −- d/s TEL) and use Blench's curves (or Crump's) to find E2E_2 (the conjugate depth after the jump) for the given qq and HLH_L.
  • d/s floor level == d/s HFL −- (d/s depth required for the jump) == TWL − E2- \,E_2 (with a safety margin of 0.5-1 m).
  • Length of the horizontal floor =5 (E2−E1)= 5\,(E_2 - E_1) (about 5×5\times height of jump) – the glacis length is included with a slope of 3:1.

Step 6: Total length of floor and cutoffs.

  • Total length from Bligh's/Khosla's criterion: Bligh L=C HL = C\,H with HH = max static head; or by Khosla's exit gradient.
  • U/s cutoff depth =1.0R= 1.0R-1.5R1.5R below u/s HFL; d/s cutoff depth =1.5R= 1.5R-2R2R below the d/s bed.

Step 7: Thickness of impervious floor. Check Khosla's pressure at key points and take the thickness

t=43⋅hG−1t = \frac{4}{3}\cdot\frac{h}{G-1}

at the toe of the glacis (max thickness), provide about 0.6 m at the ends. Taper thickness along the floor. The d/s floor under the jump should also resist the dynamic forces.

Step 8: Protection works. U/s and d/s aprons (blocks and inverted filter) with launching aprons of length 1.51.5-2×2\times scour depth; and check exit gradient GE≤G_E \le safe value.

✓ Answer checked by Claude Opus 5.5 (high effort)

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