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Rigid pavement thickness by IRC procedure

Short answer

The IRC:58 procedure involves collecting design parameters, assuming a trial thickness, computing radius of relative stiffness, then calculating edge and corner load stresses, temperature warping stresses, and friction stress. Critical stress combinations are checked against permissible stress, thickness is revised by trial, and traffic correction and joint design are applied.

Discuss the step by step procedure for the determining of rigid pavement thickness based on IRC guidelines.

The design follows IRC:58 (Guidelines for the Design of Plain Jointed Rigid Pavements for Highways), based on the Westergaard/Bradbury/Pickett-Ray approach.

  1. Collect data - design wheel load (5100 kg for highways, 4100 kg for small roads), tyre pressure, radius of contact area, flexural strength (modulus of rupture), E, Poisson's ratio and thermal coefficient of concrete; modulus of subgrade reaction k (on top of the sub-base); traffic (CVPD), growth rate and design life.
  2. Design traffic - find the commercial vehicles at the end of construction, classify the traffic (A to G) and note the thickness adjustment.
  3. Assume a trial slab thickness h and the joint spacing (transverse L, longitudinal width B).
  4. Radius of relative stiffness l=[Eh312(1−μ2)k]1/4l=\left[\dfrac{Eh^3}{12(1-\mu^2)k}\right]^{1/4}.
  5. Load stresses - edge load stress (IRC chart based on the modified Westergaard equation) and corner load stress (Westergaard's formula as modified by Kelly, σc=3Ph2[1−(a2l)1.2]\sigma_c=\frac{3P}{h^2}\left[1-\left(\frac{a\sqrt2}{l}\right)^{1.2}\right]).
  6. Temperature (warping) stresses - from the temperature differential between top and bottom: Bradbury's formula σte=C E α t2\sigma_{te}=\dfrac{C\,E\,\alpha\,t}{2} with coefficient C from L/l and B/l; corner warping stress σtc=Eαt3(1−μ)a/l\sigma_{tc}=\dfrac{E\alpha t}{3(1-\mu)}\sqrt{a/l}.
  7. Frictional stress σf=WLf2×104\sigma_f=\dfrac{WLf}{2\times10^4} (W in kg/m3, L in m).
  8. Check critical combinations - (a) summer midday, edge: σe+σte−σf\sigma_e+\sigma_{te}-\sigma_f; (b) winter midday, edge: σe+σte+σf\sigma_e+\sigma_{te}+\sigma_f (with the winter ΔT\Delta T); (c) night, corner: σc+σtc\sigma_c+\sigma_{tc}. Each must not exceed the permissible flexural stress (modulus of rupture divided by a factor of safety, or checked by the fatigue stress ratio in IRC:58-2002/2015).
  9. Revise the thickness by trial until the stresses are safe; apply the traffic correction (A to G) to the thickness.
  10. Joints and steel - design contraction, expansion and longitudinal joints, dowel bars at transverse joints and tie bars at longitudinal joints (IRC:58 / IRC:15).

✓ Answer checked by Claude Opus 5.5 (high effort)

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