- 2072 Chaitra · 8 marks
FFT of {1,1,2,4,3,1,2,1} by DIT-FFT
Short answer
Use radix-2 DIT FFT with bit-reversed input order. X(k)={15, −4.1213−j2.1213, j3, 0.1213−j2.1213, 1, 0.1213+j2.1213, −j3, −4.1213+j2.1213}.
Find the FFT of the signal x[n] = {1, 1, 2, 4, 3, 1, 2, 1} using DIT-FFT algorithm.
Method: radix-2 decimation in time (N = 8, 3 stages)
Input in bit-reversed order: x(0), x(4), x(2), x(6), x(1), x(5), x(3), x(7). Each butterfly: A' = A + W·B, B' = A − W·B, with W₈⁰ = 1, W₈¹ = 0.7071 − j0.7071, W₈² = −j, W₈³ = −0.7071 − j0.7071. Stage 1 uses W₂ (= ±1), stage 2 uses W₄⁰ = 1 and W₄¹ = −j, stage 3 uses W₈⁰ … W₈³.
x(n) = {1, 1, 2, 4, 3, 1, 2, 1}
| Position | Input (bit-reversed) | After stage 1 | After stage 2 | After stage 3 = X(k) |
|---|---|---|---|---|
| 0 | 1 | 4 | 8 | 15 |
| 1 | 3 | -2 | -2 | −4.1213 − j2.1213 |
| 2 | 2 | 4 | 0 | j3 |
| 3 | 2 | 0 | -2 | 0.1213 − j2.1213 |
| 4 | 1 | 2 | 7 | 1 |
| 5 | 1 | 0 | −j3 | 0.1213 + j2.1213 |
| 6 | 4 | 5 | -3 | −j3 |
| 7 | 1 | 3 | j3 | −4.1213 + j2.1213 |
Result:
X(0) = 15
X(1) = −4.1213 − j2.1213
X(2) = j3
X(3) = 0.1213 − j2.1213
X(4) = 1
X(5) = 0.1213 + j2.1213
X(6) = −j3
X(7) = −4.1213 + j2.1213
Check: Σx(n) = 15 = X(0); the result equals the direct 8-point DFT.
Answer: X(k) = {15, −4.1213 − j2.1213, j3, 0.1213 − j2.1213, 1, 0.1213 + j2.1213, −j3, −4.1213 + j2.1213}.
✓ Answer checked by Claude Opus 5.5 (high effort)
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