- 2073 Chaitra · 8 marks
Half-controlled bridge with R load, α = 45°
Short answer
Average output voltage V_dc = 176.75 V; output DC power P_dc = V_dc²/R = 3124 W. Input power factor = V_rms/V_s = 0.954 lagging.
Figure shows below a full wave controlled rectifier with resistive load. The load voltage is 230V, 50 Hz and it is operated at firing angle 45°. Draw the waveform of output voltage, output current and ac input current. Calculate average value of output voltage, output dc power and input power factor. [Figure: single-phase half-controlled bridge — thyristors T1, T2 on top and diodes D1, D2 on bottom, fed from Vs = 220V, 50 Hz, feeding R = 10 Ω]
The circuit is a single-phase half-controlled (semi-converter) bridge: thyristors T1, T2 on top and diodes D1, D2 at the bottom, feeding . With a resistive load the output is a chopped sine wave from to in each half cycle. Assumption: the supply is taken as 230 V, 50 Hz as stated in the text (the figure shows 220 V; results for 220 V are given at the end).
P (+)
+-------+-------+
T1 T2
a o----+ +----o b
D1 D2
+-------+-------+
N (-)
R = 10 ohm between P and N
+ half: T1 (a->P), D2 (N->b); - half: T2, D1
Waveforms
| Interval | Conducting | |||
|---|---|---|---|---|
| – | none | 0 | 0 | 0 |
| – | T1, D2 | |||
| – | none | 0 | 0 | 0 |
| – | T2, D1 | (negative) |
vo, io __ __
| \ | \
---------+---\---------+---\-----
is __
| \
---------+---\---------+---/-----
|__/
45 180 225 360 (deg)
Average output voltage
V, .
Output dc power
Input power factor
RMS output voltage:
With R load, has the same rms value as : A. All real input power is consumed in R:
Answer (230 V): V, W, input PF = 0.954 lagging.
With 220 V (figure value): V, W, PF = 0.954 (PF does not depend on the supply voltage).
✓ Answer checked by Claude Opus 5.5 (high effort)
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