Skip to main content

Gas turbine 6:1: generator power output

Short answer

Compressor work 241.87 kJ/kg, turbine work 290.01 kJ/kg, net work 48.14 kJ/kg. Generator output = 16 kg/s × 48.14 = 770 kW.

A gas turbine unit has a pressure ratio of 6:1 and maximum cycle temperature of 610°C. The isentropic efficiencies of the compressor and turbine are 0.80 and 0.82 respectively. Calculate the power output in kilowatts of an electric generator geared to the turbine when the air enters the compressor at 15°C at the rate of 16 kg/s. Take cp = 1.005kJ/kgK and γ = 1.4 for the compression process, and take cp=1.11kJ/kg K and γ = 1.333 for the expansion process.

Data: rp=6r_p = 6, T3=610+273=883T_3 = 610 + 273 = 883 K, ηc=0.80\eta_c = 0.80, ηt=0.82\eta_t = 0.82, T1=15+273=288T_1 = 15 + 273 = 288 K, m˙=16\dot m = 16 kg/s. Compression: cp=1.005c_p = 1.005 kJ/kg K, γ=1.4\gamma = 1.4 (γ−1γ=0.2857\frac{\gamma-1}{\gamma} = 0.2857). Expansion: cp=1.11c_p = 1.11 kJ/kg K, γ=1.333\gamma = 1.333 (γ−1γ=0.2498\frac{\gamma-1}{\gamma} = 0.2498). Fuel mass and mechanical losses neglected.

 1        2          3        4
 --> [C] ---> [CC] ---> [T] ---> exhaust
      \================/  ==> Generator

Compressor work

T2s=T1rp0.2857=288×1.6685=480.53 KT2=T1+T2s−T1ηc=288+192.530.80=528.66 KWc=1.005(528.66−288)=241.87 kJ/kg\begin{aligned} T_{2s} &= T_1 r_p^{0.2857} = 288 \times 1.6685 = 480.53\ \text{K} \\ T_2 &= T_1 + \frac{T_{2s} - T_1}{\eta_c} = 288 + \frac{192.53}{0.80} = 528.66\ \text{K} \\ W_c &= 1.005(528.66 - 288) = 241.87\ \text{kJ/kg} \end{aligned}

Turbine work

T4s=T3rp0.2498=8831.5646=564.38 KT4=T3−ηt(T3−T4s)=883−0.82×318.62=621.73 KWt=1.11(883−621.73)=290.01 kJ/kg\begin{aligned} T_{4s} &= \frac{T_3}{r_p^{0.2498}} = \frac{883}{1.5646} = 564.38\ \text{K} \\ T_4 &= T_3 - \eta_t (T_3 - T_{4s}) = 883 - 0.82 \times 318.62 = 621.73\ \text{K} \\ W_t &= 1.11(883 - 621.73) = 290.01\ \text{kJ/kg} \end{aligned}

Power output

Wnet=Wt−Wc=290.01−241.87=48.14 kJ/kgP=m˙Wnet=16×48.14=770.3 kW\begin{aligned} W_{net} &= W_t - W_c = 290.01 - 241.87 = 48.14\ \text{kJ/kg} \\ P &= \dot m W_{net} = 16 \times 48.14 = 770.3\ \text{kW} \end{aligned}

(Turbine power = 4640.2 kW, of which the compressor absorbs 3869.9 kW.)

Answer: Power output of the generator ≈ 770 kW.

✓ Answer checked by Claude Opus 5.5 (high effort)

All Power Plant Equipment chapter 6 questions →