- 2072 Asoj · 5 marks
Short note: Dominant mode in waveguide
Short answer
The dominant mode has the lowest cutoff frequency, enabling single-mode operation without mode conversion. In rectangular waveguide (a>b) TE10 with fc=c/(2a) is dominant; in circular waveguide TE11 (fc=1.841c/(2πa)) is dominant. It offers lowest attenuation and simple field coupling.
Write a short note on dominant mode in waveguide.
The dominant mode of a waveguide is the propagating mode with the lowest cut-off frequency (longest cut-off wavelength). Below its cut-off no energy propagates; between its cut-off and that of the next higher mode, only the dominant mode can travel, which gives clean single-mode operation.
Rectangular waveguide (a > b):
fc,mn = (c/2) √((m/a)² + (n/b)²)
TE10: fc = c/(2a), λc = 2a (dominant)
TE10 has only Ey, Hx and Hz components; E is maximum at the centre of the broad wall and zero at the side walls. TM modes start at TM11, which is always higher.
Circular waveguide (radius r): dominant mode TE11 (p'11 = 1.841), fc = 1.841c/(2πr), λc = 3.41r. The lowest TM mode is TM01 (λc = 2.61r).
Why the dominant mode is used:
- Single-mode operation avoids mode conversion and distortion.
- Lowest attenuation for a given size (in rectangular guides) and simple field pattern for coupling with probes.
- Easy design of components (tees, couplers) for one known field pattern.
Example: WR-90 guide (a = 2.286 cm, b = 1.016 cm): fc(TE10) = 6.56 GHz, next mode TE20 at 13.12 GHz. It is used in the X-band (8.2–12.4 GHz), where only TE10 propagates.
✓ Answer checked by Claude Opus 5.5 (high effort)
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