- 2072 Magh · 6+2+2 marks
Magic tee, degenerate modes, dominant mode for a = 3b
Short answer
In a magic tee, H-arm input splits equally in-phase and E-arm anti-phase (S13=S23=S14=S24=1/√2). Dominant mode has the lowest cutoff; degenerate modes share the same cutoff. For a=3b, TM10, TM01, TM02, TM20 vanish; of TM11, TM21, TM12, TM11 has the lowest cutoff fc=1.054c/(2b), making it dominant.
Describe magic Tee based on S-parameters. Differentiate between dominant and degenerate modes. Consider a rectangular waveguide having dimension of a = 3b and find the dominant mode among TM01, TM10, TM11, TM21, TM12, TM02 and TM20.
Magic tee based on S-parameters
A magic tee joins an E-plane tee and an H-plane tee at one point: ports 1 and 2 collinear, port 3 the H-arm, port 4 the E-arm.
E-arm (4)
| |
-----------+ +-----------
(1) ===========+ +=========== (2)
-----------+ +-----------
/ /
/ / H-arm (3)
S-matrix (derived from symmetry, reciprocity, E–H isolation and losslessness):
| 0 0 1 1 |
[S] = (1/√2) | 0 0 1 -1 |
| 1 1 0 0 |
| 1 -1 0 0 |
- H-arm input → equal in-phase outputs at 1 and 2, nothing at E-arm.
- E-arm input → equal 180° out-of-phase outputs at 1 and 2, nothing at H-arm.
- Input at 1 → half to E-arm and half to H-arm; port 2 isolated.
- Equal in-phase inputs at 1 and 2 add at the H-arm (sum); anti-phase inputs add at the E-arm (difference).
- All ports matched, lossless, reciprocal. Uses: balanced mixers, duplexers, impedance bridges, monopulse radar.
Dominant vs degenerate modes
| Point | Dominant mode | Degenerate modes |
|---|---|---|
| Meaning | Mode with the lowest cut-off frequency | Different modes with the same cut-off frequency |
| Number | One per guide | Two or more modes sharing fc |
| Rectangular example | TE10 (a > b) | TEmn and TMmn, e.g. TE11 and TM11 |
| Circular example | TE11 | TE01 and TM11 (both use 3.832) |
| Use | Chosen for single-mode operation | Avoided; cause mode conversion |
Dominant mode among the given TM modes for a = 3b
For TM modes the field Ez ∝ sin(mπx/a)·sin(nπy/b), so m = 0 or n = 0 gives zero field. Therefore TM01, TM10, TM02 and TM20 do not exist. The remaining candidates are TM11, TM21 and TM12:
fc,mn = (c/2) √((m/a)² + (n/b)²), a = 3b
= (c/2b) √((m/3)² + n²)
TM11: √(1/9 + 1) = 1.054 -> fc = 1.054 · c/(2b)
TM21: √(4/9 + 1) = 1.202 -> fc = 1.202 · c/(2b)
TM12: √(1/9 + 4) = 2.028 -> fc = 2.028 · c/(2b)
Answer: TM11 has the lowest cut-off frequency, so it is the dominant mode among the listed TM modes (order: TM11 < TM21 < TM12; TM10, TM01, TM20, TM02 do not exist).
✓ Answer checked by Claude Opus 5.5 (high effort)
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